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Tcecarenko [31]
3 years ago
15

The diagram shows quadrilateral MNPQ.

Mathematics
2 answers:
Alenkinab [10]3 years ago
7 0

see the attached figure with letter to better understand the problem

we know that

The triangle MNR is a right triangle

Applying the Pythagorean Theorem

MN^{2} =MR^{2}+NR^{2}

Solve for MR

MR^{2}=MN^{2}-NR^{2}

in this problem we have

MN=10\ units\\NR=6\ units

substitute the values

MR^{2}=10^{2}-6^{2}

MR^{2}=64

MR=8\ units

<u>Find the length of MQ</u>

MQ=MR+RQ

we have

MR=8\ units\\RQ=NP=3\ units

substitute

MQ=8+3=11\ units

therefore

<u>the answer is</u>

MQ=11\ units


kolezko [41]3 years ago
4 0
11 units wil be your answer.here you have to draw a line from n and it will  fall line mq.now by pythagorus theorem solve it and 3 to it
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professor190 [17]

Answer:

27a + 24b

Step-by-step explanation:

Combine the like terms.

9a + 4a + 5a + 9a = 27a

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Remember, a number without a coefficent is 1.

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
Help.....................
eduard

Answer:

Answers in Explanation

Step-by-step explanation:

First Question:

\sqrt{100} + [18 ÷ 3 x 4 - 15] - (60 - 7^2 - 1)

\sqrt{100} + [24 - 15]  - (60 - 49 - 1)

\sqrt{100} + 9 - 10

10 + 9 - 10

<u>Answer = 9</u>

Second Question:

5x + 2x = 7x

5x^2 + 3x^2 = 8x^2

2x + 3x - x = 4x

2x + 3y + x + y = 3x + 4y

9x - 6x = 3x

-7y + 3x + 4x + 3y = 7x - 4y

-7x^2 + 2x^2 + 9x^2 = 8x^2

(3x^2 + 5x + 4) - (-1 + x^2) = 2x^2 + 5x + 5

(3 + 2x - x^2) + (x^2 + 8x + 5) = 10x + 8

(3x - 4) - (5x + 2) = -2x - 6

(2x^2 + 5x + 3) - (x^2 - 2x + 3) = x^2 + 7x

(3x^2 + 2x - 5) - (2x^2 - x - 4) = x^2 + 3x - 1

Third Question:

17x + 2y

(5x + 12y) + (3x + y) = 8x + 13y

17x - 8x = 9x

2y - 13y = -11y

Answer: 9x - 11y

7 0
3 years ago
What is x- 2 1/2 = 6 3/4. pls help
MAXImum [283]
X= 9 1/4 or 9.25 in decimal form
8 0
3 years ago
Read 2 more answers
8X over five -6 equals 2X +4 how do you solve that
yaroslaw [1]
You carry the 7 add the 6 put a little bit of whip cream and you got a cake ta da
6 0
4 years ago
The area of a square can be found using the equation A = s^2, where A is the area and s is the measure of one side of the square
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A = 81 square in.

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7 0
4 years ago
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