sorry this is late!!
#1 - A circular grid like this one can be helpful for performing dilations
#2 - To perform a dilation, we need a (In order to perform a dilation, students will need to know the center of dilation (which can be communicated using the coordinate grid), the coordinates of the polygon that they are dilating (also communicated using the coordinate grid), and the scale factor.)
Answer:
g(x)=3(x+3)^2-8
Step-by-step explanation:
You can solve by using these acronyms.
H. orozontal.
I. nside.
O. pposite.
Meaning that a horozontal translation would be written inside the parenthesis and the poopsite sigh you would usually (Ex. Left is usually negitave but in this case it is positive).
The other acronym is,
V. erticle.
O. utside.
S. ame.
Meaning for a vrerticle translation the number would go on the outside of the parenthesis and tha sign would be normal (Ex. Negitave would be left and positive would be right).
For this one use H.I.O sinse you are moving on a horozontal plain. You are only working with the (x-2) nothing else matters.
Since you are moving left the number will move up 3 hence the O.
<h2><u>This transformation leaves you with g(x)=3(x+3)^2-8</u></h2>
First, distribute the 100 to the (x-1) portion:
500 = 100x - 100
then, add 100 to both sides of your equation to get “x” alone on the right side:
500 + 100 = 100x - 100 + 100
600 = 100x
next, divide 100x by 100 and 600 by 100 to isolate a singular “x”:
600/100 = 100x/100
6 = x
therefore, x=6 is your solution
The first letter can be any one of 5. For each of those . . .
The second letter can be any one of the remaining 4. For each of those . . .
The third letter can be any one of the remaining 3. For each of those . . .
The fourth letter can be any one of the remaining 2. For either of those . . .
The fifth letter is the last remaining one.
Total number of possibilities = (5 x 4 x 3 x 2 x 1) =
<em> 120 ways</em> to line them up.
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their whole life on, to make sure that a lot of kids won't go through <em><u>their</u></em>
whole life stupid. You can learn everything you ever want to know there,
and it's all free. That's a pretty good deal.
