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2 years ago

15

Whats the main purpose of the frontal lobe on the brain?

1 answer:

goldenfox [79]2 years ago

8 0

There is no other part of the brain<span> where lesions can cause such a wide variety of symptoms. The </span>frontal lobes<span> are involved in motor </span>function<span>, problem solving, spontaneity, memory, language, initiation, judgement, impulse control, and social and sexual behavior.
I hope I helped! ♥ </span>

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Joe’s Car Shop received a shipment of 40 cars. The cars each weighed the same amount. The total shipment weighed 55 tons. What w

Basile [38]

If I am not wrong it is 1375 sorry if I it wrong I trued

7 0

3 years ago

What is -1 and 3/5 divided by -2/3? As a fraction.

Dennis_Churaev [7]

Answer=

mixed form=2 2/5

decimal form=2.4

exact form= 12/5

8 0

2 years ago

Which transformation maps quadrilateral EFGH to quadrilateral QRSP

statuscvo [17]

Answer:

The answer is C.) Rotation

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I'LL GIVE BRAINLIEST TO THE CORRECT ANSWER!

artcher [175]

Solution :

1st -

$- 3 \times 5 \times ( - 6) \times 4$
$- 15 \times (- 6) \times 4$
$90 \times 4$
$360$

2nd -

$- 4 \times ( - 6 )\times ( - 3) \times ( - 5)$
$24 \times ( - 3) \times ( - 5)$
$- 72 \times ( - 5)$
$360$

3rd -

$- 3 \times 4 \times ( - 2) \times ( - 7)$
$- 12 \times ( - 2) \times ( - 7)$
$24 \times ( - 7)$
$- 168$

4th -

$- 7 \times ( - 3) \times ( - 9) \times 0$
$21 \times ( - 9) \times 0$
$- 189 \times 0$
$0$

Conclusion - only third choice has negative equivalent value

5 0

1 year ago

Read 2 more answers

A cube-shaped tank that measures 4.64.6 meters on each side is full of water. If some water is drained to fill a cone with a hei

rusak2 [61]

Answer:

The amount of water left in the tank is approximately 58.1 cubic meters

Step-by-step explanation:

step 1

Find the volume of the a cube shape tank

The volume is equal to

$V=b^{3}$

we have

$b=4.6\ m$

substitute

$V=4.6^{3}=97.336\ m^{3}$

step 2

Find the volume of cone

The volume is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=2.5\ m$

$h=6\ m$

$\pi =3.14$

substitute

$V=\frac{1}{3}(3.14)(2.5)^{2}(6)$

$V=39.25\ m^{3}$

step 3

Find the difference of the volumes

$97.336\ m^{3}-39.25\ m^{3}=58.1\ m^{3}$

3 0

2 years ago