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jolli1 [7]
1 year ago
11

Martina used 3 as the value of pi to estimate the area of a circular patio that had a diameter of 26 ft.

Mathematics
1 answer:
dezoksy [38]1 year ago
6 0

Answer:

507 ft²

Step-by-step explanation:

the area (A) of a circle is calculated as

A = πr² ( r is the radius )

given diameter = 26 then r = 26 ÷ 2 = 13 , so

A = π × 13² ≈ 3 × 169 = 507 ft²

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The answer is x=11
4x-30=14
You add 30 to each side=4x=44
Then you divide 44 by 4 which=11
4 0
2 years ago
Japhus Moore's credit card statement showed a previous balance of $921.07 , a financial charge of $13.80, new purchases of $962.
lara [203]

Answer:

$906.51

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the exact area and arc length of these sectors? Please helppp
Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = \frac{90}{360} \times \pi \times 12^2 = 36\pi

2. Area of sector 2 = \frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi

3. Area of sector 3 = \frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi

4. Area of sector 4 = \frac{270}{360} \times \pi \times 6^2 = 27 \pi

5. Arc length of sector 1 = \frac{90}{360} \times 2 \times \pi \times 12 = 6\pi

6. Arc length of sector 2 = \frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi

7. Arc length of sector 3 = \frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi

8. Arc length of sector 4 = \frac{270}{360} \times 2 \times \pi \times 6 = 9\pi

4 0
3 years ago
Compute the missing data in the table for the following exponential function f (x) = (one-fourth) Superscript x.
aliina [53]

Answer:

F(4) = \frac {1}{256}

Step-by-step explanation:

Given the following mathematical function;

F(x) = \frac {1}{4^{x}}

<u>When x = 1</u>

F(1) = \frac {1}{4^{1}}

F(1) = \frac {1}{4}

<u>When x = 2</u>

F(2) = \frac {1}{4^{2}}

F(2) = \frac {1}{4*4}

F(2) = \frac {1}{16}

<u>When x = 3</u>

F(3) = \frac {1}{4^{3}}

F(3) = \frac {1}{4*4*4}

F(3) = \frac {1}{4*4*4}

<u>When x = 4</u>

F(4) = \frac {1}{4^{4}}

F(4) = \frac {1}{4*4*4*4}

F(4) = \frac {1}{256}

<u>When x = 5</u>

F(5) = \frac {1}{4^{5}}

F(5) = \frac {1}{4*4*4*4*4}

F(5) = \frac {1}{1024}

8 0
2 years ago
Please help
Mariulka [41]

Answer:

-2 <u>12</u>

-1 <u>7</u>

0 <u>2</u>

1 <u>-3</u>

2 <u>-8</u>

Step-by-step explanation:

[] With the function f(x)=2−5x we can tell that we will plug x into the equation without doing anything to it (x)

-2 ___

f(-2) = 2−5x

f(-2) = 2−5(-2)

f(-2) = 2 + 10

f(-2) = 12

-1 ___

f(-1) = 2−5x

f(-1) = 2−5(-1)

f(-1) = 2 + 5

f(-1) = 7

0 ___

f(0) = 2−5x

f(0) = 2−5(0)

f(0) = 2

1 ___

f(1) = 2−5x

f(1) = 2−5(1)

f(1) = 2 - 5

f(1) = -3

2 ___

f(2) = 2−5x

f(2) = 2−5(2)

f(2) = 2−5(2)

f(2) = 2−10

f(2) = -8

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

4 0
2 years ago
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