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Vadim26 [7]
3 years ago
14

If all of the diagonals are drawn from a vertex of a hexagon, how many triangles are formed?

Mathematics
2 answers:
stealth61 [152]3 years ago
5 0
Six, one for each vertex!
igor_vitrenko [27]3 years ago
5 0
The correct answer is 6. Have a look at the picture I have made for you:

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On B would it be X over 0.001?
Alex73 [517]
Yeah it is .........
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3 years ago
Is this the right answer?
zalisa [80]
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8 0
3 years ago
Q.1 Simplify :-<br><br>(i) (- 625 ) + 925 + 100 + (-200)​
Dmitrij [34]
825 - 625i

Hope it’s right
Best luck with your studying
3 0
2 years ago
Your sister is getting married this summer and she has asked you to help her select a D.J.
ioda
So Dave charges 150 at first and then 10.50 per each hour, so if your sister has the party going for say "h" hours, then his total charges will then be 150 + 10.5h.

now, Marvin's Mobile Music charges 135 at first, but then is more expensive per hour is 15 bucks per each hour, so if she has a party for "h" hours, then his total charges are 135 + 15h.

now, let's check when they're both equal, at how many hours will they cost your sister the same amount.

\bf 150+10.50h=135+15h\implies 150-135=15h-10.5h&#10;\\\\\\&#10;15=4.5h\implies 15=4\frac{1}{2}h\implies 15=\cfrac{9}{2}h\implies \cfrac{15}{\frac{9}{2}}=h\implies \cfrac{\frac{15}{1}}{\frac{9}{2}}=h&#10;\\\\\\&#10;\cfrac{15}{1}\cdot \cfrac{2}{9}=h\implies \cfrac{30}{9}=h\implies \cfrac{10}{3}=h\implies 3\frac{1}{3}=h

so, 3 and a third of a hour, or 3 hours and 20 minutes, they both will cost your sister the same amount, so it wouldn't matter who's hired if the party is only 3 hours and 20 minutes long.

however, after that, the one with higher hourly rate, Marvin's, gets more expensive, and she's better off hiring the one with cheaper hourly rate.

now, you can just get some mp3s and some loud speakers and nevermind the  DJs and you do it, or she can do it, I have the macarena song if you need that one.
3 0
3 years ago
V square+6v-59=0<br> answer in one equation
Tema [17]
X=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
a=1
b=6
c=-59
x=\frac{-6+/- \sqrt{(6)-4(1)(-59)} }{2(1)}
x=-3+ 2\sqrt{17} and -3- 2\sqrt{17}




8 0
3 years ago
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