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krek1111 [17]
3 years ago
8

How do you simplify 16m^2/24m^7

Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer: 2/3m^5

Step-by-step explanation: 1st Reduce the expression by cancelling the common factors.

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f as a function of x is equal to the square root of quantity x plus two; g(x) = 8x - 6 Find f(g(x)). f(g(x)) = 8 times the squar
romanna [79]

f(x)=\sqrt{x+2}

g(x)=8x-6

f(g(x))=\sqrt{(8x-6)+2}=\sqrt{8x-4}=\sqrt{4(2x-1)}=2\sqrt{2x-1}

answer: the third option

4 0
3 years ago
Robert came in first for 3/4 of his race. Express this fraction as a decimal
Rina8888 [55]
SOLUTION:

= 3 / 4

= 75 / 100

= 0.75

Therefore, Robert came in first for 0.75 of his race.

Hope this helps. :)
Have a lovely day! <3
4 0
3 years ago
Write the equation of a line that passes through the points (5,8) and (4,10). Write your answer in slope-intercept form
Alik [6]
It would be: Y=-2x+18
8 0
3 years ago
What is the equation of the line that is parallel to the given line and passes through the point (–2, 2)?
kari74 [83]
Let the equation of the given line be y=mx+a. This line has slope m and the parallel line will have the same slope.
Then the equation of the parallel line to the line y=mx+a will be y=mx+b. Since line <span>passes through the point (–2, 2), the coordinates of this point suit the equation:
</span><span>
</span><span>2=m·(-2)+b,</span>
2=-2m+b,
b=2+2m 
and the equation is y=mx+2m+2. 
You should only to paste correct m from the given equation.
<span />
8 0
4 years ago
What is the radius of a sphere with a volume of 1/6 pie
Yakvenalex [24]

Answer:

\large\boxed{the\ radius\ R=\dfrac{1}{2}}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

We have

V=\dfrac{1}{6}\pi

Substitute:

\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi        <em>divide both sides by π</em>

\dfrac{4}{3}R^3=\dfrac{1}{6}          <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}

4R^3=\dfrac{1}{2}          <em>divide both sides by 4</em>

R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}

3 0
3 years ago
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