Answer:
3.41 g
Explanation:
<em>A chemist adds 260.0 mL of a 0.0832 M potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask.</em>
Step 1: Given data
- Volume of the solution (V): 260.0 mL (0.2600 L)
- Molar concentration of the solution (C): 0.0832 M (0.0832 mol/L)
Step 2: Calculate the moles (n) of potassium permanganate added
We will use the following expression.
n = C × V
n = 0.0832 mol/L × 0.2600 L = 0.0216 mol
Step 3: Calculate the mass corresponding to 0.0216 moles of potassium permanganate
The molar mass of potassium permanganate is 158.03 g/mol.
0.0216 mol × 158.03 g/mol = 3.41 g
Answer:
it ends up in our dirt and oceans/bodies of water
The values of N, log N and ln N are all worked out below.
We have the number N as 8.99
hence;
1) lnN = ln(8.99) = 2.196
log N = log (8.99) = 0.954
2) If we have ln N as 3.949
N = e^3.949 = 51.88
So;
log N = log (51.88) = 1.715
3) log N = 0.134
N = Antilog (0.134 ) = 1.36
ln N = ln (1.36) = 0.307
Learn more: brainly.com/question/4210362
31.79 g Cu / 63.5 g/mol Cu ---> 0.5
0.5 * (2/1) ---> 1
1 * 107.9 g/mol Ag
107.9 grams
Answer:
Explanation:
Acceleration (a) is the change in velocity (Δv) divided by the change in time (Δt).
