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marta [7]
3 years ago
15

Describe the angiosperm life cycle step by step.

Chemistry
2 answers:
Amanda [17]3 years ago
7 0

Answer:

Explanation:

1)In the flower's male parts, the anthers, diploid microsporangium undergo meiosis giving rise to microspores. ...

2)In the flower's ovules, the megasporocyst undergoes meiosis creating four megaspores. ...

3)Next pollination occurs.

Tresset [83]3 years ago
4 0

Answer:

The adult, or sporophyte, phase is the main phase of an angiosperm's life cycle. As with gymnosperms, angiosperms are heterosporous. Therefore, they generate microspores, which will produce pollen grains as the male gametophytes, and megaspores, which will form an ovule that contains female gametophytes.

1)In the flower’s male parts, the anthers, diploid microsporangium undergo meiosis giving rise to microspores.  These haploid microspores will eventually give rise to haploid pollen grains

2)In the flower’s ovules, the megasporocyst undergoes meiosis creating four megaspores.  Only one of these four megaspores survives and undergoes three mitotic divisions to produce an eight-nucleate embryo sac, or mature megagametophyte

3)Next pollination occurs.  The pollen grain travels to the stigma via wind, insects or other transportational devices.  Once on the stigma it generates a pollen tube down the style.

4)Two sperm travel down each pollen tube into the ovary.  One sperms fertilizes the egg to produce  a zygote and the other fertilizes the central cell to form the endospore.

5)The zygote will give rise to an embryo and will be enclosed with the endospore in a seed.  The endospore gives the embryo energy to germinate.

6)Poison ivy’s seeds are typically dispersed by animals.  However the seeds are buoyant which makes dispersal by water possible as well.

7)Once the seed does germinate, the diploid zygote will eventually turn into another sporophyte. This process is about three years in poison ivy

8)The cycle starts over.

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Answer:

This experiment is uncontrolled because two different masses of substance A are used.

Explanation:

A controlled experiment is a structured experiment aimed at testing a particular observation or observations. The setup of a controlled experiment helps to determine the reason why a particular observation occurs and what must have led to it.

In the experiment highlighted above, different masses of a substance were used, they were heated to different temperatures. The set up does not show any correlation between the masses of substances heated and the temperatures. It is even difficult to try to predict the hypothesis for this kind of experimental set up. All the variables in play can best be assumed to be independent of one another.

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3 years ago
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What are the steps to finding an items density?
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There are 5 steps:
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3 0
3 years ago
if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g
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5 0
3 years ago
Complete and balance the following equation:
sertanlavr [38]
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.

You get: BrO3 + N2H4 -> Br2 + N2 + H2O

# of Br: 1x1 = 1 # of Br: 2x1 = 2
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H: 4x1 = 4. H: 2x1 = 2

Br:
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O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.

H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.

N:
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You end up with the complete and balanced equation:

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4 0
4 years ago
In one compound of nitrogen and oxygen, 0.615 grams of nitrogen combines with 0.703 grams of oxygen. In another 1.27 grams of ni
Orlov [11]

Answer:

Answer in explanation

Explanation:

In the first case, we divide each of the masses by the respective atomic masses:

N =0.615/14 = 0.043928571428571

O = 0.703/16 = 0.0439375

It can be seen here that the values are similar, hence the formula is NO

now let us look at the second data set:

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We now divide by the smallest

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The formula here is thus NO2.

It can be seen that there are different oxides of nitrogen here which clearly indicates the law of multiple proportion.

4 0
3 years ago
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