All categories

3 years ago

4k/19m simplify this fraction

Mathematics

2 answers:

grin007 [14]3 years ago

7 0

4k/19m Final result : 4km /19

Step by step solution :Step 1 : k Simplify /19 Equation at the end of step 1 : k (4 • /) • m 19 Advertising SkipStep 2 :Final result : 4km/ 19

Olin [163]3 years ago

5 0

The answer is 4km over 19

You might be interested in

PLEASE HELP!!! what is 1.46 X 10 ^-7 written in standard form?

taurus [48]

I think you just have to rewrite it to -1.46×10^-7

8 0

3 years ago

The resulting row 1 entries are

Ilia_Sergeevich [38]

Are 2,3,4,5,6,7,8,9 your welcome

6 0

3 years ago

How many roots does the equation -2x3 = 0 have? 3 2 1 0

pickupchik [31]

-2x^3 = 0
solving for x you divide both sides by -2
x^3 = 0
Now take the cube root of each side
x = cube root of zero
x = 0
It has 1 root.
The root is zero

4 0

3 years ago

Read 2 more answers

Given that sectheta = -37/12 what is the value of cottheta for pi/2 < theta< pi?

lys-0071 [83]

Answer:

$cotg(\theta) = -\frac{12}{35}$

Step-by-step explanation:

The cotangent of theta is:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

For pi/2 < theta< pi

This means that the angle is in the second quadrant. In the second quadrant, the cosine is negative and the sine is positive. This means that the cotangent will be negative.

Secant:

$sec(\theta) = \frac{1}{\cos{\theta}}$

In this question

$sec(\theta) = -\frac{37}{12}$

$-\frac{37}{12} = \frac{1}{\cos{\theta}}$

Using cross multiplication

$-37\cos{\theta} = 12$

$37\cos{\theta} = -12$

$\cos{\theta} = -\frac{12}{37}$

Now we apply the following trigonometric identity:

$\sin{\theta}^{2} + \cos{\theta}^{2} = 1$

$\sin{\theta}^{2} + (-\frac{12}{37})^{2} = 1$

$\sin{\theta}^{2} = 1 - (-\frac{12}{37})^{2}$

$\sin{\theta}^{2} = 1 - \frac{144}{1369}$

$\sin{\theta}^{2} = \frac{1369 - 144}{1369}$

$\sin{\theta} = \pm \sqrt{\frac{1225}{1369}}$

Since the angle is in the second quadrant, the sine is positive.

$\sin{\theta} = \frac{35}{37}$

Finally, the cotangent:

$cotg(\theta) = \frac{\cos{\theta}}{\sin{\theta}}$

$cotg(\theta) = \frac{-\frac{12}{37}}{\frac{35}{37}}$

$cotg(\theta) = -\frac{12}{35}$

4 0

4 years ago

Read 2 more answers

A function $f$ has a horizontal asymptote of $y = -4,$ a vertical asymptote of $x = 3,$ and an $x$-intercept at $(1,0).$ Part (a

Masja [62]

1. $f$ has a horizontal asymptote at $y=-4$

This means that

$\displaystyle\lim_{x\to\pm\infty}f(x)-(-4)=0$

(for at least one of these limits)

2. $f$ has a vertical asymptote at $x=3$

This means that $f$ has a non-removable discontinuity at $x=3$ . Since $f$ is some rational function, there must be a factor of $x-3$ in its denominator.

3. $f$ has an $x$ -intercept at (1, 0)

This means $f(1)=0$ .

(a) With

$f(x)=\dfrac{ax+b}{x+c}$

the second point above suggests $c=-3$ . The first point tells us that

$\displaystyle\lim_{x\to\pm\infty}\frac{ax+b}{x-3}+4=0=\lim_{x\to\pm\infty}\frac{ax+b+4x-3}{x-3}=0$

In order for the limit to be 0, the denominator's degree should exceed the numerator's degree; the only way for this to happen is if $a=-4$ so that the linear terms vanish.