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3 years ago

5

4k/19m simplify this fraction

2 answers:

grin007 [14]3 years ago

7 0

<span> 4k/19m </span>Final result : 4km /19

Step by step solution :<span>Step 1 :</span> k Simplify /19 <span>Equation at the end of step 1 :</span> k (4 • /) • m 19 <span>Advertising Skip</span><span>Step 2 :</span>Final result :<span> 4km/ 19 </span>

Olin [163]3 years ago

5 0

The answer is 4km over 19

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GREYUIT [131]

Answer:

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$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

Step-by-step explanation:

Given

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The height of triangle h = 6x-3

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The Area of the triangle has the formula

A = 1/2 × b × h

substituting b = 2x+1, h = 6x-3 and A = 240

$240\:=\:\frac{1}{2}\:\left(2x+1\right)\:\times \left(6x-3\right)$

$480=\left(2x+1\right)\left(6x-3\right)$

$480=12x^2-3$

Subtract 480 from both sides

$12x^2-3-480=480-480$

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$3\left(2x+\sqrt{161}\right)\left(2x-\sqrt{161}\right)=0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$2x+\sqrt{161}=0\quad \mathrm{or}\quad \:2x-\sqrt{161}=0$

solving

$2x+\sqrt{161}=0$

$2x=-\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{-\sqrt{161}}{2}$

$x=-\frac{\sqrt{161}}{2}$

also solving

$2x-\sqrt{161}=0$

$2x=\sqrt{161}$

Divide both sides by 2

$\frac{2x}{2}=\frac{\sqrt{161}}{2}$

$x=\frac{\sqrt{161}}{2}$

Therefore, the values of x which would give an area of 240m² would be:

$x=-\frac{\sqrt{161}}{2},\:x=\frac{\sqrt{161}}{2}$

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