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3 years ago

At a cafe , the cook uses a recipe that calls for eggs and milk have a proportional relationship. Complete the table.

Mathematics

2 answers:

SVEN [57.7K]3 years ago

7 0

Answer:

Milk over eggs is gonna be 3 over 1

Step-by-step explanation:

jonny [76]3 years ago

5 0

Answer:

(in this order ) 4,9, 3/1

Step-by-step explanation:

You might be interested in

How Many times do at least 2 odd numbers show up when you count from 0 to 999? Show your work.

postnew [5]

let's count from 0 to 999

0, 1, 2, 3, ooh, look, there are 2 odd numbers, 4, 5, look another one, 6, 7, another!

we can see that every time you count from 0 to 999, at least 2 odd numbers show up

so answer is 1 time (because if 2 odd numbers or 20 odd numbers show up, it's still at least 2 odd numbers)

I think you really want to know how many times a pair off numbers occur together

like 33, 313 or 333, but not 31

that is interesting

in the first 10's 11 is only one

in each odd 10, in the 100's reigon, there is only 1 pair of odds

so 11, 33, 55, 66, 77, 99 or 6 pairs in the pre-100's zone

in the 100's zone, we have 101, 110-119, 121, 131, 141, 151, 161, 171, 181, 191 or 19 numbers with pairs of odds

in 200's, it's the same as pre-100's, 6 pairs

in the 300's zone, it's like 100's so 19 pairs

in the 400 zone, it's like 200's, 6 pairs

in 500's zone, it's like 100's, so 19 pairs

in the 600 zone, it's like 200's, 6 pairs

in 700's zone, it's like 100's, so 19 pairs

in the 800 zone, it's like 200's, 6 pairs

in 900's zone, it's like 100's, so 19 pairs

so a total of 6+19+6+19+6+19+6+19+6+19=125 pairs of odds

8 0

3 years ago

there are 12 girls and 18 boys in a class what is th largest number of groups they can be split into and have the same number of

aalyn [17]

15 groups

Step-by-step explanation:

boys can be split in 9 groups of 2 and the girls can be split in 6 groups of 2

adding this 9+6=15

7 0

3 years ago

Please help with this

Mrac [35]

Answer:

im trying to find it i cant im sooooryyy 7

Step-by-step explanation:

8 0

3 years ago

A group of 10 students participate in chess club, karate club, or neither.

Ira Lisetskai [31]

Answer: Option B

$P(A|B)=0.50$

Step-by-step explanation:

We look for the conditional probability of A given B.

This is written as:

$P(A|B) = \frac{P(A\ and\ B)}{P(B)}$

First we must find the probability of A and B

There are 10 students in total. Note that of those 10 students only 2 of them are at the same time in the karate club and in the chess club

Therefore:

$P(A\ and\ B)=\frac{2}{10}$

There are 10 students in total. Note that of those 10 students only 4 of them are in the chess club

Then:

$P(B)=\frac{4}{10}$

Finally:

$P(A|B) = \frac{P(0.2)}{0.4}=0.50$

5 0

4 years ago

Simplify –2 + {[5 x(-2) +(-6)] + 24 }

Inessa [10]

Answer: −10x + 16

The equation simplified is −10x + 16

Step-by-step explanation:

Hope this helps =)

6 0

2 years ago