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Sophie [7]
3 years ago
9

Solve using elimination 2x+2y=8 3x+2y=12

Mathematics
1 answer:
kogti [31]3 years ago
4 0

\left\{\begin{array}{ccc}2x+2y=8\\3x+2y=12&\text{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+2y=8\\-3x-2y=-12\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-x=-4\to\boxed{x=4}\\\\\text{Put the value of x to the first equation:}\\\\2(4)+2y=8\\8+2y=8\qquad\text{subtract 8 from both sides}\\2y=0\qquad\text{divide both sides by 2}\\\boxed{y=0}\\\\Answer:\ \boxed{x=4\ and\ y=0\to(4,\ 0)}

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Find the area of rectangle, where length is 15 cm and breadth is 7 cm.​
Varvara68 [4.7K]

Question :-

  • Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .

Answer :-

  • Area of Rectangle is 105 cm² .

\rule {195pt} {2pt}

Diagram :-

\sf{15 \: cm} \\ \quad \quad  \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\   \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\  \\  \\ \end{array}}  \:  \:  \sf {7 \: cm}\end{gathered}\end{gathered}

\rule {195pt} {2pt}

Solution :-

\quad \quad » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.

For calculating the Area of Rectangle , we will use the Formula :-

  • \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth}

Therefore , by Substituting the given values in the above Formula :-

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7}

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105}

Hence :-

  • Area of Rectangle = 105 cm² .

\underline {\rule {195pt} {4pt}}

Additional Information :-

\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \:  \: More \: Formulas \:  \:  \dag}}}} \\  \\  \\  \footnotesize \bigstar  \:  \bf{Area \: _{Square} = Side \times Side}  \\  \\  \\   \footnotesize\bigstar  \:  \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Triangle} =  \frac{1}{2} \times Base \times Height } \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Parallelogram} = Base \times Height} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Trapezium} =  \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}

5 0
2 years ago
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