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r-ruslan [8.4K]
3 years ago
14

Which numbers are necessary to solve this problem?

Mathematics
2 answers:
Harman [31]3 years ago
8 0
Add, multiply then, add then divide, so A.
Bad White [126]3 years ago
5 0
Hello there.

<span>Which numbers are necessary to solve this problem? 

Brian goes to the gym 3 times a week. He exercises for 45 minutes each visit. Fifteen of those minutes are spent on weights and the rest are spent on the treadmill. 

How much time does Brian spend on the treadmill in 4 weeks?

Answer: </span><span>3 times a week, 45 minutes, 15 minutes, 4 weeks
</span>
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Please help will give branlist
nata0808 [166]

Answer:

The file will help

Step-by-step explanation:

7 0
3 years ago
A chemist is using 328 milliliters of a solution of acid and water. If 14.4% of the solution is acid, how many milliliters of ac
gregori [183]

Answer:

47.432 (rounds to 47.4 or 47.43)

Step-by-step explanation:

14.4 * 328/100 = 47.232

5 0
3 years ago
SOMEONE PLEASEE HELP ME WITH THIS!!! I NEED TO GET DONE
klasskru [66]

Answer:

B. 1

Step-by-step explanation:

-   \frac{1}{2} (10) + 6 =  - 5 + 6 = 1

6 0
2 years ago
Used to find the total number of outcomes with coumpound events
Dahasolnce [82]
F<span>undamental Counting Principle (FCP) is the answer </span>
5 0
3 years ago
{ TOPIC -- TRIGONOMETRIC IDENTITIES }
UkoKoshka [18]
LHS ⇒ RHS:
Identities:
[1] cos(2A) = 2cos²(A) - 1 = 1 - 2sin²(A)
[2] sin(2A) = 2sin(A)cos(A)
[3] sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
[4] cos(A + B) = cos(A)cos(B) - sin(A)sin(B)

cos(x) - cos(x + 2Θ)
= cos(x) - (cos(x)cos(2Θ) - sin(x)sin(2Θ))    [4]
= cos(x) - cos(x)(1 - 2sin²(Θ)) + sin(x)(2sin(Θ)cos(Θ))    [1] [2]
= cos(x) - cos(x) + 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin(Θ)(sin(Θ)cos(x) + sin(x)cos(Θ))
= 2sin(Θ)sin(x + Θ)
8 0
2 years ago
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