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3 years ago

Which numbers are necessary to solve this problem?

Mathematics

2 answers:

Harman [31]3 years ago

8 0

Add, multiply then, add then divide, so A.

Bad White [126]3 years ago

5 0

Hello there.

<span>Which numbers are necessary to solve this problem?

Brian goes to the gym 3 times a week. He exercises for 45 minutes each visit. Fifteen of those minutes are spent on weights and the rest are spent on the treadmill.

How much time does Brian spend on the treadmill in 4 weeks?

Answer: </span><span>3 times a week, 45 minutes, 15 minutes, 4 weeks
</span>

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Simple geometry problem

vova2212 [387]

Answer:

Step-by-step explanation:

I gather that you need to find the area of the sector and then subtract from it the area of the segment to get the area of the triangle (although there are other ways in which to find the area of the triangle).

The area of a sector is:

$A=\frac{\theta}{360}\pi r^2$ where our angle is given as 34, pi is 3.1415, and the radius is 5:

$A=\frac{34}{360}(3.1415)(25)$ and if you multiply and divide that all out you get that the area of the sector is:

A = 7.417

Now subtract from it the area of the segment, 2.209. to get the area of the triangle:

7.417 - 2.209 = 5.208

7 0

3 years ago

Read 2 more answers

Evaluate the expression

nevsk [136]

Simplifying
-16 + 23 (-4) + -3
Multiply 23 x -4
Add -16 + -92=-108
Add -108-3= -111 <------Answer

8 0

3 years ago

Read 2 more answers

Find the value of x If necessary, you may learn what the markings on a figure indicate.

Igoryamba

Answer:

x=36°

Step-by-step explanation:

Find the answer with the theorems related to isosceles triangle and the exterior angle theorem

4 0

2 years ago

The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%

vagabundo [1.1K]

Answer:

1) $\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

2) $p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

$\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}$

Where O rpresent the observed values and E the expected values.

State the null and alternative hypothesis

Null hypothesis: The distribution is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

$E = \% Grand total$

$E_{Catfish}=500*0.3=150$

$E_{Bass}=500*0.15=75$

$E_{Bluegill}=500*0.4=200$

$E_{Pike}=500*0.15=75$

Part 1: Calculate the statistic

$\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313$

$\chi^2 =16.313$

Calculate the critical value

First we need to calculate the degrees of freedom given by:

$df= (categories-1)=(4-1)= 3$

Since the confidence provided is 95% the significance would be $\alpha=1-0.95=0.05$ and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be $\chi^2_{crit}=7.815$

We can calculate also the p value:

$p_v =P(\chi^2_{3}>16.313)=0.000978$

And we got the same decision reject the null hypothesis at 5% of significance.

5 0

3 years ago

A typical virus is a packet of protein and DNA (or RNA) and can be spherical in shape. The influenza A virus is a spherical viru

DochEvi [55]

Answer:

10⁻⁶

Step-by-step explanation:

Since the volume of saliva coughed up by my friend is 0.0100 cm³ and 10⁺⁹ of this volume contains the virus. The volume containing the virus is thus V = 0.0100 cm³ × 10⁺⁹ = 0.0100 × 10⁺⁹ cm³ = 0.0100 × 10⁺⁹ × 10⁻⁶ m³ = 0.0100 × 10⁺¹⁵ m³.

Now, since the flu virus is spherical, its volume is v = 4πr³/3 where r is its radius.

Let n flu viruses be contained in the volume V of flu viruses coughed out by my friend.

So n × v = V

v = V/n

4πr³/3 = V/n

r = ∛(3V/4πn)

substituting the value of V into the equation, we have

r = ∛(3 × 0.0100 × 10⁺¹⁵ m³/4πn)

r = (∛0.03/4πn) × 10⁻⁵ m

r = 0.1336/∛n × 10⁻⁵ m

r = 1.336/∛n × 10⁻⁶ m

Since the factor 10⁻⁶ is found in the radius, the order of magnitude of the influenza virus that have just landed on me are of the order 10⁻⁶

3 0

3 years ago