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inysia [295]
2 years ago
15

Complete the description of what happens to a figure when the given sequence of transformations is applied to it: (x,y) -> (-

x,y);(x,y) -> (0.8x,0.8y);(x,y)->(x - 4, y + 4).

Mathematics
1 answer:
RoseWind [281]2 years ago
5 0
Omg I wish I could help I am not in this top level ‍♂️
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A line has the equation -5x -14y +168 = 0
valkas [14]

Answer:

y = -5/14x + 12

Step-by-step explanation:

add 14y to both sides to isolate variables and divide everything by 14 to get 1y and boom

6 0
2 years ago
Line AB has endpoints A(-4,5) and B(3,5). What is the x-coordinate of a point C such that B is the midpoint of line AC
Ipatiy [6.2K]
Easy peasy

the midpoint between (x_1,y_1) and (x_2,y_2) is
(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})
just average them

so given that (3,5) is the midpoint of (-4,5) and (x,y)
(\frac{-4+x}{2},\frac{5+y}{2})=(3,5)
so by logic
\frac{-4+x}{2}=3 and \frac{5+y}{2}=5
times both sides by 2 for everybody
-4+x=6 and 5+y=10
add 4 to both sides for left one and minus 5 from both sides for right
x=10 and y=5

the coordinate of point C is (10,5)
the x coordinate is 10
7 0
3 years ago
Variable termes X-12-3X+22
adell [148]

Answer: x + 12 = 3x + -22

12 + x = 3x + -22

Reorder the terms:

12 + x = -22 + 3x

Solving

12 + x = -22 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

12 + x + -3x = -22 + 3x + -3x

Combine like terms: x + -3x = -2x

12 + -2x = -22 + 3x + -3x

Combine like terms: 3x + -3x = 0

12 + -2x = -22 + 0

12 + -2x = -22

Add '-12' to each side of the equation.

12 + -12 + -2x = -22 + -12

Combine like terms: 12 + -12 = 0

0 + -2x = -22 + -12

-2x = -22 + -12

Combine like terms: -22 + -12 = -34

-2x = -34

Divide each side by '-2'.

x = 17

Simplifying

x = 17

7 0
2 years ago
The force, F (Newtons), between two objects is inversely proportional to the square of the distance, d (metres), between them.
snow_lady [41]

Answer:

d = 1.46 m

Step-by-step explanation:

We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:

From the question given above,

F is inversely proportional to square of d. This can be written as:

F ∝ 1/d²

F = K/d²

Cross multiply

K = Fd²

But:

Force (F) = 0.006 N

Distance (d) = 4 m

Constant (K) =?

K = Fd²

K = 0.006 × 4²

K = 0.006 × 16

K = 0.096 Nm²

Therefore, the relationship between the force (F) and the distance (d) is:

F = K/d²

F = 0.096 / d²

Finally, we shall determine the distance when the force is 0.045 N. This can be obtained as follow:

Force (F) = 0.045 N

Constant (K) = 0.096 Nm²

Distance (d) =?

F = K/d²

0.045 = 0.096 / d²

Cross multiply

0.045 × d² = 0.096

Divide both side by 0.045

d² = 0.096 / 0.045

Take the square root of both side.

d = √(0.096 / 0.045)

d = 1.46 m.

7 0
2 years ago
Find the acute angle between the lines. round your answer to the nearest degree. 6x − y = 4, 4x y = 9
garri49 [273]
Picture please and thank you

8 0
2 years ago
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