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3 years ago

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Complete the description of what happens to a figure when the given sequence of transformations is applied to it: (x,y) -> (-

x,y);(x,y) -> (0.8x,0.8y);(x,y)->(x - 4, y + 4).

1 answer:

RoseWind [281]3 years ago

5 0

Omg I wish I could help I am not in this top level ‍♂️

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Pls help me answer my worksheet

bearhunter [10]

Step one know that across from 128 is 128 because of vertical angles
step two a straight line =180 so 128 -180 = 52
step three know you know 3k+4=52 so subtract 4 from 52 and that gives you 48 then divide by 3 to find k and 48/3 is 16
so k +16
because 16x3 is 48 then add 4 which is 52 and 52 plus 128 is 180

8 0

3 years ago

Please help answer the following question

Elena L [17]

Answer:

D

Step-by-step explanation:

The unmarked angle of the triangle is also 40o. The triangle is marked with two equal sides (isosceles).

<2 + 40 + 40 = 180 Combine the left

<2 + 80 = 180 Subtract 80 from both sides

<2 = 180 - 80

<2 = 100 degrees.

That's not the answer. We have to solve for x

<2 = x + 106

100 = x + 106 Subtract 106 from both sides

100 - 106 = x

x = - 6

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3 years ago

Alex is driving across the country.He needs to drive 8 hours a day for 15 days in a order to get to his destination. So far, he

Nadusha1986 [10]

52/8 is 6.5 which is 6.5 days 15-6.5 is 8.5 and 8.5 • 8 is 68. 68+52 is the same as 15•8 so i’m pretty sure the answer is 68

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3 years ago

What triangle pairs can be mapped to each other using a single tranlation

shepuryov [24]

Answer: I think Figure 4 is the correct one

Step-by-step explanation:

It is not possible to map the triangle MNP and CDE together using just a single translation in Figure 3. With Figure 4, we can use a translation to map the triangle MNP and the triangle CDE. Accordingly, in the diagram, the triangle MNP and the triangle CDE can be translated to each other.

8 0

3 years ago

Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?

BaLLatris [955]

Answer:

$Vertex = (\frac{1}{2},\frac{7}{4})$

Step-by-step explanation:

Given

$f(x) = x^2 - x +2$

Required

The vertex

We have:

$f(x) = x^2 - x +2$

First, we express the equation as:

$f(x) = a(x - h)^2 +k$

Where

$Vertex = (h,k)$

So, we have:

$f(x) = x^2 - x +2$

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

$f(x) = x^2 - x +2$

$f(x) = x^2 - x + (-\frac{1}{2})^2+2 -(-\frac{1}{2})^2$

$f(x) = x^2 - x + \frac{1}{4}+2 -\frac{1}{4}$

Expand

$f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2 -\frac{1}{4}$

Factorize

$f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2 -\frac{1}{4}$

Factor out x - 1/2

$f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}$

Compare to: $f(x) = a(x - h)^2 +k$

$h = \frac{1}{2}$

$k = \frac{7}{4}$

Hence:

$Vertex = (\frac{1}{2},\frac{7}{4})$

8 0

3 years ago

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