1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Llana [10]
3 years ago
8

On an architects plan for a house, the scale reads 1/2 in. = 5 ft. How long is the actual length of a room that's 2 in. Long on

the drawing?
Mathematics
1 answer:
Nady [450]3 years ago
6 0
1/2:5

1:10

2:20

The actual length of the room is 20 feet.
You might be interested in
What are the answers to this someone please help.
statuscvo [17]

1234567890233572o7o5y345uo22u.3936584643728284/43794729237932972478864966666666666666666666666666666666663870434573428734907 goood luck!

6 0
3 years ago
Identify the coordinates of the point (3,-2), translated 5 units left and 6
kap26 [50]

Answer:

(- 2, 4 )

Step-by-step explanation:

A translation of 5 units left means subtract 5 from the original x- coordinate.

A translation of 6 units up means add 6 to the original y- coordinate.

Thus

(3, - 2 ) → (3- 5, - 2 + 6 ) → (- 2, 4 )

3 0
4 years ago
Can anyone help me integrate :
worty [1.4K]
Rewrite the second factor in the numerator as

2x^2+6x+1=2(x+2)^2-2(x+2)-3

Then in the entire integrand, set x+2=\sqrt3\sec t, so that \mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt. The integral is then equivalent to

\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt

Note that by letting x+2=\sqrt3\sec t, we are enforcing an invertible substitution which would make it so that t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3} requires 0\le t or \dfrac\pi2. However, \tan t is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which \tan t>0 so that |\tan t|=\tan t. This allows us to write

=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt
=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt

We can show pretty easily that

\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C
\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C
\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C
\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C

which means the integral above becomes

=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C
=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C

Back-substituting to get this in terms of x is a bit of a nightmare, but you'll find that, since t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}, we get

\sec t=\dfrac{x+2}{\sqrt3}
\sec^2t=\dfrac{(x+2)^2}3
\tan t=\sqrt{\dfrac{x^2+4x+1}3}
\cot t=\sqrt{\dfrac3{x^2+4x+1}}
\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}
\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}

etc.
3 0
3 years ago
How can you use unit rates to solve pricing problems?​
melomori [17]

Answer:

a ratio is a comparison of two numbers or measurements

the objects being compared are called the terms of the ratio.

if the tow terms are different units this is called a rate.

example:

David covers 600 miles in 8 hours and John covers 380 miles in 5 hours. Who is driving faster ?

solution:

Distance covered by David in 1 hour is

=  600 / 8  

=  75 miles per hour

Distance covered by John in 1 hour is

=  380 / 5  

=  76 miles per hour

When we compare the above unit rates (Distance covered in 1 hour), John is driving faster than David.

5 0
3 years ago
Read 2 more answers
What’s the volume of the cylinder
FrozenT [24]

Answer:

188.496 mm^3 (or 188.495559 mm^3 if you want to be specific)

Step-by-step explanation:

The radius would be the distance from the middle of the circle on top, we are given that the diameter of the circle is 4mm, the radius is half of that so you would get 2 as the radius (or R). H is the height of the cylinder which is 15 mm, so plugging it in (pi * (2^2) * 15) would get you 188.496 mm^3 (rounded of course).

3 0
3 years ago
Other questions:
  • In a race, a bicyclist travels 3/4 of a mile in 1/4 hour. Determine the unit rate for the speed in miles per hour.
    5·1 answer
  • SOMEONE PLEASE ANSWER ASAP THIS FOR BRAINLIEST!!!!
    15·1 answer
  • What can you conclude about the survey
    10·1 answer
  • Nicole has $9 to spend on cards she finds friends with the same amount of money to split the cost of a set one set cost $27 each
    6·1 answer
  • A donut machine can make 3000 donuts in 10 hours. How long would it take the machine to make 600 donuts? How many donuts are mad
    12·1 answer
  • Express the value of each tangent ratio to the nearest tenth or as a fraction
    11·1 answer
  • Pls just answer it with A B C D makes life simpler
    5·1 answer
  • You were given 10 math problems for homework. You completed 6/10 of them at school. Which equation shows how to find the fractio
    8·2 answers
  • How many ten thousand are in 1,000,000?​
    10·1 answer
  • PLS HELP ME ASAP ILL GIVE 50 POINTS AND BRAINIEST TO WHOEVER ANSWER CORRECTLY AND SHOWS THEIR WORK PLAS I NEED HELP ON THIS
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!