Answer:
Width of 6ft and length of 9ft
Step-by-step explanation:
The sandbox has a ratio of 2:3. If you plug the numbers in with the ratio, you can find the actual dimensions.
Let x be the length
Let y be the width
(Length)
2in / 3ft = 6in / (x)ft
2in / 3ft = 6in / <u><em>9ft </em></u>
(Width)
2in / 3ft = 4in / (y)ft
2in / 3ft = 4in / <em><u>6ft</u></em>
Area = Length x Width
Area = 34 x 14
Area = 476 yd²
Answer: 476 yd²
The given terms are two terms apart, so their difference is twice the difference of adjacent terms.
![a_8-a_6=2d=61-53=8\\\\d=\dfrac{8}{2}=4](https://tex.z-dn.net/?f=a_8-a_6%3D2d%3D61-53%3D8%5C%5C%5C%5Cd%3D%5Cdfrac%7B8%7D%7B2%7D%3D4)
The value of d is 4.
The answer is B, 3/4 is greater than 3/5
3/4=0.75
3/5=0.6
0.75 is greater than 0.6
X= 7 I already solve it before check other questions.