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r-ruslan [8.4K]
3 years ago
14

Can someone help me please I'm really having trouble with this and I hate it

Mathematics
2 answers:
Grace [21]3 years ago
8 0
3^4 x 3^-5 x ^-2
= 3^(4 - 5 -2)
= 3^-3
      1
= -------
    3^3
AleksandrR [38]3 years ago
3 0

Answer:

Oikjj

Step-by-step explanation:

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By solving substitution y=4x-6<br> Y= 5x how I need steps
stiv31 [10]

Answer:

x= -6

Step-by-step explanation:

y=4x-6

y=5x, so where ever you see y, put 5x there.

hence, 5x=4x-6

5x-4x=-6

x= -6

5 0
3 years ago
The base of a cube is 36cm. What is the volume of the cube?
sasho [114]

Answer:

46656

Step-by-step explanation:

8 0
3 years ago
Select all expressions that represent a correct solution to the equation 6(x+4)=20
Sergeeva-Olga [200]

Answer:

D. 20 ÷ 6 − 4

E. 1/6(20 − 24)

F. (20−24) ÷ 6

Step-by-step explanation:

6(x + 4) = 20

6(x) + 6(4) = 20

6x + 24 = 20

     - 24  - 24

6x = -4

/6    /6

x = -4/6 or x = -2/3

D. 20 ÷ 6 − 4

20/6 - 4

20/6 - 24/6

-4/6 = -2/3

E. 1/6(20 − 24)

1/6(-4)

-4/6 = -2/3

F. (20 − 24) ÷ 6

- 4 / 6

-4/6 = -2/3

Hope this helps!

3 0
2 years ago
A line passes through the points
masha68 [24]

Answer:

y=-2x+7

enter the point into point slope form to find the slope and then use one of the points in point slope form  and rearrange it to have y by itself

4 0
3 years ago
Use Midpoint and Slope Formulas to complete the tables below.1. Find the midpoint of RP, given the coordinates R (5, 8) and P (3
poizon [28]

The midpoint formula for a segment is:

x_m,y_{_m}=\frac{(x_1+x_2)}{2},\frac{(y_1+y_2)}{2}

apply to points R and P

\begin{gathered} x_m,y_m=\frac{(5+3)}{2},\frac{(8+6)}{2} \\ x_m,y_m=\frac{8}{2},\frac{14}{2} \\ x_m,y_m=(4,7) \end{gathered}

using the definition of slope find the slope of the segment

m=\frac{y_2-y_1}{x_2-x_1}

apply to points R and P

\begin{gathered} m=\frac{8-6}{5-3} \\ m=\frac{2}{2} \\ m=1 \end{gathered}

to lines are parallel when the slopes are the same

\mleft\Vert m=1\mright?

two lines are perpendicular when the product of the slopes is equal to -1

\begin{gathered} m\cdot\perp m=-1 \\ 1\cdot\perp m=-1 \\ \perp m=-\frac{1}{1} \\ \perp m=-1 \end{gathered}

7 0
1 year ago
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