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RUDIKE [14]
3 years ago
5

Plz helpp. In a high school with 5,000 students, the number of text messages sent by each student during a particular month was

recorded. The mean number of text messages sent during the month was 55 per student.
If the data was normally distributed, and if the standard deviation of the data was 4 text messages, which of these is the BEST estimate for the number of students who sent fewer than 51 text messages during the month?


A) 800

B) 1,200

C) 1,600

D) 1,700
p.s i already did it and its a)800
Mathematics
1 answer:
vampirchik [111]3 years ago
8 0

Answer:

A) 800

Step-by-step explanation:

I am on a challenge and I need points plus you told me

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Some friends of yours collected books for a book drive. They collected 64 Fiction, and 48 Non-Fiction books. They asked you to m
Cloud [144]

As all of the bundles have the same content inside, so assuming that there is x number of Fiction books and y number of Non-fiction books in each bundle.

Let n be the total number of bundles that my team can send.

There are 64 Fiction books, so

nx=64 ...(i)

Or x=64/n ...(ii)

also, there are 48 Non-Fiction books, so

ny=48 ...(iii)

Or y=48/n ...(iv)

Observing that the numbers x, y, and n are counting numbers and from equations (i) and (iii), n is the common factor of 64 and 48.

The possible common factors of 64 and 48 are,

n=1,2,4,8, and 16.

So, my team can send 1,2,3,4,8 or 16 bundles of books.

Now, from equations (ii) and (iv),

For n=1:

x=64/1=64

y=48/1=48

So, for 1 bundle the number of Fiction and Non-fictions books are 64 and 48 respectively.

For n=2:

x=64/2=32

y=48/2=48

So, for 2 bundles, the number of Fiction and Non-fictions books are 32 and 24 respectively.

For n=4:

x=64/4=16

y=48/4=12

So, for 4 bundles, the number of Fiction and Non-fictions books are 16 and 12 respectively.

For n=8:

x=64/8=8

y=48/8=6

So, for 8 bundles, the number of Fiction and Non-fictions books are 8 and 6 respectively.

For n=16:

x=64/16=4

y=48/16=3

So, for 16 bundles, the number of Fiction and Non-fictions books are 4 and 3 respectively.

8 0
3 years ago
Round and estimate 0.9% of 74
skelet666 [1.2K]
The answer is 6.7 bc .09 times 74 equals 6.66 so you round the 6 to a 7.
7 0
3 years ago
|9-(-1)|= simplify the expression
Hitman42 [59]

Answer:

10

Step-by-step explanation:

Remove parentheses.

|9+1|

Simplify  9+1  to 10.

|10|

simplify

10

7 0
3 years ago
In a standard normal distribution, about _________% of the scores fall above a z-score of 3.00
Katarina [22]

The normal rule to remember is 68-95-99.7, i.e. plus or minus three sigma corresponds to 99.7% of the probability. That leaves 0.3% in the two tails, or 0.15% in the tail above 3 sigma.

Answer: 0.15%


7 0
3 years ago
What is Greater 980 squared root or 4π^2
Rudik [331]

Answer:

The greater number is 4π^2.

Step-by-step explanation:

1) 4π^2 = 39.4784176044

2) \sqrt{980} = 31.304951685

4π^2 is greater.

7 0
3 years ago
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