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RUDIKE [14]
3 years ago
5

Plz helpp. In a high school with 5,000 students, the number of text messages sent by each student during a particular month was

recorded. The mean number of text messages sent during the month was 55 per student.
If the data was normally distributed, and if the standard deviation of the data was 4 text messages, which of these is the BEST estimate for the number of students who sent fewer than 51 text messages during the month?


A) 800

B) 1,200

C) 1,600

D) 1,700
p.s i already did it and its a)800
Mathematics
1 answer:
vampirchik [111]3 years ago
8 0

Answer:

A) 800

Step-by-step explanation:

I am on a challenge and I need points plus you told me

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43%

Step-by-step explanation:

Last month, 72.

This month, 126.

Last month, ebony had 72/126 in her account to what she has this month. 72/126 as a percentage.

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Given b(x) = [X+41, what is b(-10)?<br> – 10<br> -6<br> 6<br> 14
OLEGan [10]

Option C: 6 is the value of b(-10)

Explanation:

The given expression is b(x)=|x+4|

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To find the value of b(-10), let us substitute x=-10 in the given expression.

Thus, substituting x=-10 in the expression, we have,

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Adding the terms, we get,

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Lubov Fominskaja [6]

Step-by-step explanation:

So the question is easy ....The thing that you need to do here is ...You should divide area by length....and you will get your answer....

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3 years ago
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