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Anastaziya [24]
3 years ago
8

Kristin owns a bakery called Kristin’s cakes and n’ such and is considering lowering the price of her cakes. Kristen polls her c

ustomers and determines that she can sell 100 cakes each week when she changes $25 each. She also discovers that every $1 decrease in price of the cake, she will sell 5 more cakes. The portion of the graph below represents kristen’s projected weekly revenue for each decrease in price.
Which of the following are true? Select all that apply.

Mathematics
2 answers:
den301095 [7]3 years ago
8 0
1,3,5
4 looks like true but decreasing but 2 dollars also gives max revenue, so I not sure about it
AleksAgata [21]3 years ago
3 0

Answer:

  • If Kristin does not decrease the price of her cakes,her projected weekly revenue from cake sales will be $ 2500.

Since if she is not decreasing her price that means the point will be on the Revenue axis.

and the point is 2500.

Hence, the statement is True.

  • If Kristin decreases the price of her cakes, her projected weekly revenue will also decrease.

This statement is False as while decreasing the price from $ 2 to $ 3 the revenue remains same.

  • If Kristin decreases the price of her cake by $ 1, her projected weekly revenue will be $ 2520.

This statement is True.

Since when there is a decrease in $ 1 this means that 5 cakes increases and price per cake is $ 24.

i.e. 105 cakes are being sold at a rate of $ 24 each.

Hence, the total revenue is:

24×105=$ 2520.

  • Kristin should decrease the price of her cake by $ 3 ,in order to obtain the maximum weekly revenue.

This statement is False.

Since, the maximum revenue is obtained when there is no decrease.

  • Kristin will receive the same revenue if she sells the cake for $ 24 or $ 21.

This statement is True.

Since when she sells for $ 24 each she has to sell 105 cakes.

so, revenue obtained is:

24×105=$ 2520.

When she sells for $ 21, she has to sell 120 cakes and the revenue obtained is:

20×120=$ 2520.

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Simplify the radical expression. Please explain how you got your answer.<br><br> √25/4
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3 years ago
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
insens350 [35]
1) We have that there are in total 6 outcomes If we name the chips by 1a, 1b, 3 ,5 the combinations are: 1a,3 \ 1b, 3 \1a, 5\ 1b, 5\ 3,5\1a,1b. Of those outcomes, only one give Miguel a profit, 1-1. THen he gets 2 dollars and in the other cases he lose 1 dollar. Thus, there is a 1/6 probability that he gets 2$ and a 5/6 probability that he loses 1$.
2) We can calculate the expected value of the game with the following: E=\frac{1}{6}*2- \frac{5}{6} *1. In general, the formula is E= \sum{p*V} where E is the expected value, p the probability of each event and V the value of each event. This gives a result of E=2/6-5/6=3/6=0.5$ Hence, Miguel loses half a dollar ever y time he plays.
3) We can adjust the value v of the winning event and since we want to have a fair game, the expecation at the end must be 0 (he must neither win or lose on average). Thus, we need to solve the equation for v:
0=\frac{1}{6}v -\frac{5}{6} =0. Multiplying by 6 both parts, we get v-5=0 or that v=5$. Hence, we must give 5$ if 1-1 happens, not 2.
4) So, we have that the probability that you get a red or purple or yellow sector is 2/7. We have that the probability for the blue sector is only 1/7 since there are 7 vectors and only one is blue. Similarly, the 2nd row of the table needs to be filled with the product of probability and expectations. Hence, for the red sector we have 2/7*(-1)=-2/7, for the yellow sector we have 2/7*1=2/7, for the purple sector it is 2/7*0=0, for the blue sector 1/7*3=3/7. The average payoff is given by adding all these, hence it is 3/7.
5) We can approach the problem just like above and set up an equation the value of one sector as an unknown. But here, we can be smarter and notice that the average outcome is equal to the average outcome of the blue sector.  Hence, we can get a fair game if we make the value of the blue sector 0. If this is the case, the sum of the other sectors is 0 too (-2/7+0+2/7) and the expected value is also zero.
6) We want to maximize the points that he is getting. If he shoots three points, he will get 3 points with a probability of 0.30. Hence the average payoff is 0.30*3=0.90. If he passes to his teammate, he will shoot for 2 points, with a success rate of 0.48. Hence, the average payoff is 0.48*2=0.96. We see that he should pass to his player since 0.06 more points are scored on average.
7) Let us use the expections formula we mentioned in 1. Substituting the possibilities and the values for all 4 events (each event is the different profit of the business at the end of the year).
E=0.2*(-10000)+0.4*0+0.3*5000+0.1*8000=-2000+0+1500+800=300$
This is the average payoff of the firm per year.
8) The firm goes even when the total profits equal the investment. Suppose we have that the firm has x years in business. Then x*300=1200 must be satisfied, since the investment is 1200$ and the payoff per year is 300$. We get that x=4. Hence, Claire will get her investment back in 4 years.
8 0
3 years ago
Read 2 more answers
Please answer this multiple choice question CORRECTLY for 30 points and brainliest!!
JulijaS [17]

Solve the inequality for x:

5x - 3 ≤ 7x +7

Subtract 7x from each side:

-2x -3 ≤ 7

Add 3 to each side:

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Divide both sides by -2, also when dividing  both sides of an inequality you flip the direction of the inequality sign:

x ≥ -5

The dot will be on -5, because the inequality includes equal to, the dot is solid and is greater than, the arrow will point to the right.

The correct answer is D.

4 0
3 years ago
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