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Anni [7]
3 years ago
11

Find and simplify an expression for the area of two rows of b squares with side lengths of b centimeters. Please help!

Mathematics
1 answer:
Ronch [10]3 years ago
6 0

Answer:

The complete area of the given figure is (2 b^3) cm^2

Step-by-step explanation:

Total number of rows = 2

Squares in each row = b

So, the total number of  squares in 2 rows = 2 x ( Squares in 1 row ) = 2 x  b

Also, side length of 1 square = b cm

As we know, AREA OF SQUARE  = SIDE x SIDE

So here, area of 1 square  = Side x side  = b cm  x b cm = (b^2) cm^2

⇒ The area of total (2b) squares  = 2 b x ( Area of  1 square)

= 2 b \times (b^2)  = 2 b^3

Hence, the complete area of the given figure is (2 b^3) cm^2

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6x — 5y = 15<br> x = y + 3<br> х =<br> y =
butalik [34]

<em>Replace all occurrences of x with y + 3 in each equation.</em>

<em>Replace all occurences of x in 6x - 5y = 15 with y + 3.</em>

<em>6 (y+3) -5y = 15</em>

<em>x = y + 3</em>

<em>Simplify 6 (y + 3) - 5y.</em>

<em>Simplify each term.</em>

<em>Apply the distributive property.</em>

<em>6y + 6 · 3 - 5y = 15</em>

<em>x = y + 3</em>

<em>Multiply 6 by 3.</em>

<em>6y + 18 - 5y = 15</em>

<em>x = y + 3</em>

<em>Subtract 5y from 6y.</em>

<em>y + 18 = 15</em>

<em>x = y + 3</em>

<em>Move all terms not containing y to the right side of the equation.</em>

<em>Subtract 18 from both sides of the equation.</em>

<em>y = 15 - 18</em>

<em>x = y + 3</em>

<em>Subtract 18 from 15.</em>

<em>y = -3</em>

<em>x = y + 3</em>

<em>Replace all occurences with y with -3 in each equation.</em>

<em>Replace all occurences of y in x = y + 3 with -3.</em>

<em>x = (-3) + 3</em>

<em>y = -3</em>

<em>Add -3 and 3.</em>

<em>x = 0</em>

<em>y = -3</em>

<em>The solution to the system is the complete set of ordered pairs that are valid solutions.</em>

<em>(0,-3)</em>

<em>The result can be shown in multiple forms. </em>

<em>Point Form:</em>

<em>(0,-3)</em>

<em>Equation Form:</em>

<em>x = 0, y = -3</em>

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3 years ago
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3 years ago
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3 years ago
ANSWER AT YOUR OWN WILL THX!
matrenka [14]

Using proportions, it is found that:

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<h3>What is a proportion?</h3>

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One example of application of proportions is for percentage problems, as a percentage is given by the amount a divided by the total amount b, and multiplied by 100%.

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8 0
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Solve the equation 20 + 0.44x = 19 + 1.69x.
artcher [175]

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<h3>What is meant by an equation?</h3>

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