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Vedmedyk [2.9K]
3 years ago
12

6x — 5y = 15 x = y + 3 х = y =

Mathematics
2 answers:
Lisa [10]3 years ago
7 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The required values are :

  • x = 0
  • y =  - 3

Refer to the attachment for solution ~

butalik [34]3 years ago
5 0

<em>Replace all occurrences of x with y + 3 in each equation.</em>

<em>Replace all occurences of x in 6x - 5y = 15 with y + 3.</em>

<em>6 (y+3) -5y = 15</em>

<em>x = y + 3</em>

<em>Simplify 6 (y + 3) - 5y.</em>

<em>Simplify each term.</em>

<em>Apply the distributive property.</em>

<em>6y + 6 · 3 - 5y = 15</em>

<em>x = y + 3</em>

<em>Multiply 6 by 3.</em>

<em>6y + 18 - 5y = 15</em>

<em>x = y + 3</em>

<em>Subtract 5y from 6y.</em>

<em>y + 18 = 15</em>

<em>x = y + 3</em>

<em>Move all terms not containing y to the right side of the equation.</em>

<em>Subtract 18 from both sides of the equation.</em>

<em>y = 15 - 18</em>

<em>x = y + 3</em>

<em>Subtract 18 from 15.</em>

<em>y = -3</em>

<em>x = y + 3</em>

<em>Replace all occurences with y with -3 in each equation.</em>

<em>Replace all occurences of y in x = y + 3 with -3.</em>

<em>x = (-3) + 3</em>

<em>y = -3</em>

<em>Add -3 and 3.</em>

<em>x = 0</em>

<em>y = -3</em>

<em>The solution to the system is the complete set of ordered pairs that are valid solutions.</em>

<em>(0,-3)</em>

<em>The result can be shown in multiple forms. </em>

<em>Point Form:</em>

<em>(0,-3)</em>

<em>Equation Form:</em>

<em>x = 0, y = -3</em>

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