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3 years ago

11

How do you do dividing 33 photos into two groups at the ratio is 4 to 7?

1 answer:

Nookie1986 [14]3 years ago

4 0

If you have a problem with ratio, i would start with adding the numbers of the ratio, in our case:4+7=11

this means that the "whole" could be dividied into 11 parts, of which the first entity in the ratio has 4 and the other 7

since there are 33 photos, then each part is 33/11=3 photos.

so the two groups are 4*3=12
and

7*3=21

12 and 21 photos.

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taurus [48]

Answer:

The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 27 - 1 = 26

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0518

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample.

In this question:

$n = 27, s = 21.4$ . So

$M = 2.0518\frac{21.4}{\sqrt{27}}$

$M = 8.45$

The margin of error for the 95% confidence interval for the mean score of all such subjects is of 8.45.

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3 years ago

How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem

masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

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3 years ago

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lidiya [134]

42/number of sides in a hexagon
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3 years ago

Sadie simplified the expression √54a^7b^3, where a>=0, as shown: √54a^7b^3= √3^2•6•a^2•a^5•b^2•b=3ab √6a^5b

Tamiku [17]

Answer:

We are to find the error made by Sadie and then find the correct simplification.

The error Sadie made is that she wrote $a^7$ as $a^2 * a^5$ instead of $a^6 * a$ .

The square root of $a^6$ is $a^3$ and so she could have further simplified.

The correct simplification is shown below:

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3 years ago