Question

In which quadrants do solutions for the inequality y ≤ 2/7x +1 exist?

Answer 1

I know this isnt an answer, however! the other answer is wrong i'm doing the quiz right now and i did that one and got no points whatsoever.  

Just so nobody else has do their quiz again!

Answer 2

All four quadrants

Explanation:

We have the following inequality:

$y \leq \frac{2}{7}x+1$

So the first step we need to perform is to plot the line:

$y = \frac{2}{7}x+1$

$If \ x=0 \\ \\ y=\frac{2}{7}(0)+1 \\ \\ y=1 \\ \\ \\ If \ y=0: \\ \\ 0=\frac{2}{7}(x)+1 \\ \\ x=-\frac{7}{2}=-3.5$

So the line passes through the points:

$(0,1) \ and \ (-3.5,0)$

To find the shaded region, let us take a point, namely, the origin and test it in the inequality:

$y \leq \frac{2}{7}x+1 \\ \\ 0\leq \frac{2}{7}(0)+1 \\ \\ 0\leq 1 \ True!$

Since this is true, then the shaded region includes this point. This is shown below and as you can see the solutions exist in all four quadrants.

Learn more:

Inequalities: brainly.com/question/12890742

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