Answer: the speed of the plane in still air is 135 km/h
the speed of the wind is 23 km/h
Step-by-step explanation:
Let x represent the speed of the plane in still air.
Let y represent the speed of the wind.
Flying to England with a tailwind a plane averaged 158km/h. This means that the total speed of the plane is (x + y) km/h. Therefore,
x + y = 158 - - - - - - - - - - - - - -1
On the return trip, the plane only averaged 112 km/h while flying back in the same wind. This means that the total speed of the plane is (x - y) km/h. Therefore,
x - y = 112 - - - - - - - - - - - - - -2
Adding equation 1 to equation 2, it becomes
2x = 270
x = 270/2 = 135 km/h
Substituting x = 135 into equation 2, it becomes
135 - y = 112
y = 135 - 112
y = 23 km/h
Well...this is a proportion problwm. for every 16 cups I have 1 gallon, so I can write that as:
16 cups
-----------
1 gallon
this value will be proportional to 1/4 a gallon equal "so many" cups. let's equal the unknown about of cups to x.
16 cups______ x cups
-----------.... = ..... ----------
1 gallon _____ 1/4 gallons
I can cross multiply to find x.
1 gallon • x cups = 16 cups • 1/4 gallons
16 times 1/4 is the same as 16/4, which equals 4.
1 gallon • x cups = 4 cups gallons
divide both sides by gallons
x cups = 4 cups
so! 1/4 of a gallon equals 4 cups.
Answer:
The equation –3y = 15 – 4x rewritten in slope-intercept form is
✔ y = (4/3)x – 5
.
The y-intercept is
✔ –5
and the slope of the line is
✔ 4/3
.
Line
✔ B
is the graph of the line –3y = 15 – 4x.
12/18
6/9
2/3
Simply in common factor you know and keep doing it
12/18
BCD:6
2/3
Hello! I can help you!
22. Okay. What we need to do for this one is subtract fraction.l, because we are looking for how much more the second container holds than the first. We need to covert them to like denominators, which in this case is 8 5 3/4 = 5 6/8. Because 6/8 is less than 7/8, we need to regroup by adding 8 and turning the 5 into a 4. The problem would become like this: 4 14/8 - 1 7/8. When you subtract both numbers, you get 3 7/8. There. The second container holds 3 7/8 more gallons of water than the first.
23.
a. 15 student speeches will last 1 1/2 minutes each. In this case, we just simply multiply the fractions by multiply straight across. Multiply the top numbers together and the bottom numbers together. 1 1/2 is 3/2 a an improper fraction. Make 15 have a denominator of 1. 15/1 * 3/2 is 45/2 or 22 1/2 as a mixed number. It will take 22 1/2 minutes to give the speeches.
b. Okay. The teacher makes a 15 minute intro. Let’s add the time it takes to make the speeches and the teacher’s intro. 22 1/2 + 15 0/2 is 37 1/2. Yes. There is enough time to record everyone.
c. There are 60 minutes in 1 hour. Subtract the total amount taken on the camera from 60. 0/2 is less than 1/2. Again, regroup by adding 2 to make 2/2, and crossing out 60, so it becomes 59. 59 2/2 - 37 1/2 is 22 1/2. There are 22 1/2 minutes left on the digital camera.
