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zhannawk [14.2K]
3 years ago
9

Find the surface area of a cylinder with a radius of 38 centimeters and a height of 123 centimeters

Mathematics
2 answers:
Rzqust [24]3 years ago
6 0
Hello!

To find the surface area of a cylinder you use the equation

SA = 2 \pi rh+ 2 \pi  r^{2}

SA is surface area
r is radius
h is height

Put in the values you know

SA = 2 \pi (38)(123) + 2 \pi * 38^{2}

Square the number

SA = 2 \pi (38)(123) + 2 \pi  * 1444

Multiply 38 and 123

SA = 2 \pi  * 4674 + 2  \pi  * 1444

Multiply 2 and 4674

SA = 9348 \pi  + 2 \pi  * 1444

Multiply the 2 and 1444

SA = 9348 \pi  + 2888 \pi

Add

SA = 12236 \pi = 38440.53

The answer is 12236 pi or about 38440.53

Hope this helps!
Elan Coil [88]3 years ago
3 0
38440.53 Is the surface area of the cylinder
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1/10

Step-by-step explanation:

(3/5) - (1/2)

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Step-by-step explanation:

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2 years ago
F
AnnZ [28]

Answer:

The average rate of change of f(x) = x^2 +6x+13  is 12

The average rate of change of f(x) =- x^2 +6x+13 is 10

Step-by-step explanation:

The  average rate of change  of f(x) over an interval between 2 points (a ,f(a)) and (b ,f(b)) is the slope of the  secant line  connecting the 2 points.

We can calculate the average rate of change between the 2 points  by

\frac{f(b) - f(a)}{b -a}-------------------(1)

(1) The average rate of change of the function f(x) = x^2 +6x+13  over  the interval 1 ≤ x ≤ 5

f(a) = f(1)

f(1) = (1)^2 +6(1) + 13

f(1) =1+6+13

f(a) =  20---------------------(2)

f(b) = f(5)

f(5) = (5)^2 +6(5)+13

f(5) = 25 +30 +13

f(5) = 68-----------------------(3)

The average rate of change between (1 ,20) and (5 ,68 ) is

Substituting eq(2) and(3) in (1)

=\frac{f(5) - f(1)}{5-1}

=\frac{68 -20}{5-1}

= \frac{48}{4}

=12

This means that the average of all the slopes of lines tangent to the graph of f(x) between  (1 ,20) and (5 ,68 ) is 12

(2) The average rate of change of the function  f(x) = -x^2 +6x+13 over  the interval -1 ≤ x ≤ 5

f(a)  = f(-1)

f(1) = (-1)^2 +6(-1) + 13

f(1) =1-6+13

f(1) = 8---------------------(4)

f(b) = f(5)

f(5) = (5)^2 +6(5)+13

f(5) = 25 +30 +13

f(5) = 68-----------------------(5)

The average rate of change between (-1 ,8) and (5 ,68 ) is

Equation (1) becomes

\frac{f(5) - f(-1)}{5-(-1)}

On substituting the values

=\frac{68 - 8}{5-(-1)}

=\frac{60}{5+1}

=\frac{60}{6}

= 10

This means that the average of all the slopes of lines tangent to the graph of f(x) between  (-1 ,8) and (5 ,68 ) is 10

4 0
3 years ago
What is the value of x and y?
ladessa [460]

Answer:

x=16 and y=9

Step-by-step explanation:

2y+30=3y+21[Diagonals of parallelogram are equal]

30-21=3y-2y

y=9

3y=2x-5[Diagonals of parallelogram are equal]

3×9=2x-5

27=2x-5

2x=27+5

x=32/2=16

5 0
2 years ago
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