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3 years ago

What conclusion could be derived by comparing the central tendencies of the two data sets?

Mathematics

1 answer:

STatiana [176]3 years ago

5 0

Answer:

General comparisons based around median? It's a vague question. Can you expound?

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Please answer this question I can't seem to figure it out I have even asked my parents.

nika2105 [10]

Answer:

j. Pam, Tia, Veronica, Lily (if it's youngest to oldest)

Step-by-step explanation:

If Tia is 8 yrs old and she's 2 yrs older than Pam, then Pam must be 6 yrs old. Pam si 5 yrs younger than Veronica who must be 11 + 4 = 15.

Tia: 8 yrs.

Veronica: 11 yrs

Pam: 6 yrs.

Lily: 15

4 0

2 years ago

Read 2 more answers

What is the midpoint of this ?

dybincka [34]

Answer:

M(-2; -5)

Step-by-step explanation:

7 0

2 years ago

12<br> Using side lengths only, could the triangles be similar?<br> 0.5<br> m05 1 1.5

Murljashka [212]

Answer:

$\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}$

Step-by-step explanation:

$\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/$

$\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}$

$\text{Despite this, let's check the ratios}$

$\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5$

$\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}$

8 0

3 years ago

A group of people were asked if they had run a red light in the last year. 290 responded "yes", and 177 responded "no". Find the

GuDViN [60]

Answer:

0.621

Step-by-step explanation:

Number of people that have run a red light in the last year = 290

Number of people that have not run a red light in the last year = 177

Total number of respondents = 290 + 177

= 467

Pr(if a person is chosen at random, they have run a red light in the last year) = $\frac{number of people who has run the red light last year}{total number of respondents}$

= $\frac{290}{467}$

= 0.621

The probability that if a person is chosen at random, they have run a red light in the last year is 0.621.

6 0

3 years ago

you are taking a math course in which there will be four tests, each worth 100 points. you have scores of 89, 93, and 98 on

sergij07 [2.7K]

89+93+98 = 280

360 - 280 = 80 marks is needed for the last test

8 0

3 years ago