How does the volume of a cylinder change if the radius is quadrupled and the height is reduced to a third of its original size?

2 answers:

8 0

Oh yay, proportional thinking! (Vicious sarcasm). Alright, let's do this:

Volume of the cylinder = π(h)r^2
New volume = π(h/3)(4r)^2
= (1/3)π(h)(16r^2)
=16*(1/3)π(h)r^2
=(16/3)π(h)r^2

Therefore, it's D. Though it's spelled pi, and you should really use the ^ symbol.

GenaCL600 [577]3 years ago

7 0

Answer:

the correct answer is D

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One day at a supermarket, 258 fruits were sold in the morning, and 5/6 of the number of fruits sold in the morning were sold in

astra-53 [7]

Answer:

258 fruits.

Step-by-step explanation:

We have been given that one day at a supermarket, 258 fruits were sold in the morning, and 5/6 of the number of fruits sold in the morning were sold in the afternoon.

So the fruits sold in the afternoon will be 5/6 of 258.

$\text{The number of fruits sold in afternoon}=\frac{5}{6}\times 258$

$\text{The number of fruits sold in afternoon}=5\times 43$

$\text{The number of fruits sold in afternoon}=215$ .

Further, we are told that the number of fruits sold in the next afternoon increased by 20% compared to the number of fruits sold in the afternoon the previous day.

So the number of fruits sold in the next afternoon will be:

$\text{The number of fruits sold in next afternoon}=215+(\frac{20}{100}\times 215)$