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3 years ago

Use words to describe the following sequence,then find the next 3 numbers in the sequence 49,64,81,11...

Mathematics

1 answer:

solmaris [256]3 years ago

8 0

The next three numbers in the sequence are 121, 144, and 169

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If it's 7:30 what time will it gets in an hour and a quarter?

slava [35]

Answer:

8:55

Step-by-step explanation:

7:30 plus 1 hour is 8:30. Quarter is 25 or 1/4. Then you add 8:30 plus 25 which gives you 8:55.

7 0

3 years ago

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Solve using substitution y=3x-5 2x+5y=-42

Paul [167]

Answer:

Solution point is (-1,-9)

Step-by-step explanation:

Put the value of y in the first equation into the second equation.

2x + 5(3x - 5) = - 42 Remove the brackets on the left
2x + 15x - 25 = - 42 Combine like terms on the left
17x - 25 = - 42 Add 25 to both sides
17x - 25 + 25 = - 42 + 25 Do the addition
17x = - 17 Divide by 17
17x/17 = -17/17 Do the division
x = - 1

=======

Solve for y

y = 3x - 6
x = -1
y = 3(-1) - 6
y = -3 - 6
y = - 9

6 0

3 years ago

MATH HELP PLEASE!!!

olga55 [171]

i dont know sorry, maybe someone else can help you?

6 0

3 years ago

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Simplify. √25 - √40 ? help please.

melomori [17]

Answer:

5-2√10

Step-by-step explanation:

5-2√10

break them down

√25=5

so 5-√40

then simplify

5-2√10

7 0

3 years ago

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Carlos is filling a spherical balloon with water. if he increases the volume of the balloon from 4,188.79 cubic centimeters to 1

Harrizon [31]

We know that the volume of a sphere of radius r is given by

$V=\frac{4}{3}\pi r^3$

Now, we have been given the initial volume was 4,188.79 cubic centimeters. Let us find the radius at this time.

Substituting the value of volume in the above equation, we get

$4,188.79=\frac{4}{3}\pi r^3\\
\\
4\pi r^3=4,188.79 \times 3\\
\\
r^3=\frac{4188.79 \times 3}{4\pi}\\
\\
r^3=1000\\
\\
r=10$

Now, the final volume is given by 14,137.167 cubic centimeters. Thus, we have

$14137.167 =\frac{4}{3}\pi r^3\\
\\
4\pi r^3=14137.167 \times 3\\
\\
r^3=\frac{14137.167\times 3}{4\pi}\\
\\
r^3=3375\\
\\
r=15$

Now, let us find the surface areas for these two radii.

For $r=10$

Surface area is given by

$S=4\pi r^2\\
\\
S=4\times 3.14 \times (10)^2\\
\\
S=1256 \text{ square centimeters}$

Similarly, for

$r=15\\
\\
S=4\times 3.14\times (15)^2\\
\\
S=2826 \text{ square centimeters}$

Therefore, the increase in the surface area is given by

$\Delta S= 2826-1256= 1570 \text{ square centimeters}$

Hence, the average rate at which the surface area is changing is given by

$\frac{1570}{12}=130.8$

Therefore, the average rate at which the surface area is changing is given by 130.8 square centimeters per second.

7 0

3 years ago