Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each ho

Question

3 years ago

14

Steve is trying to increase his average pace per mile by running hills. The hill on 1st Avenue rises 3 vertical feet for each ho

rizontal foot. The hill on 16th Avenue rises 1 vertical foot for every 3 horizontal feet.
Which hill will be more difficult for Steve to run up? Explain your reasoning.

Mathematics

2 answers:

marissa [1.9K] · Answer 1 · 2022-01-26T11:07:09+03:00

marissa [1.9K]3 years ago

7 0

1st Avenue would be more difficult because it’s rise and run is for every one foot forward it is 3 feet up. Meanwhile avenue 16th would start at (3,1) and the rise and run would be for every 3 feet it would go up 1 foot.

Liula [17] · Answer 2 · 2022-01-26T12:15:31+03:00

Answer:

The first Avenue will be more difficult for Steve to run up.

Step-by-step explanation:

Before to get started, please take a look at the attached sketch below.

Take in account that slope is a number that describes the steepness of a line. It can be computed through the ratio of the vertical change to the horizontal change.

According to this, the slope of the first avenue is 3/1 and the slope of the 16th avenue is 1/3. Therefore, the first avenue inclination is greater than 16 th avenue. This means that the first avenue requires more effort to be run up.