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3 years ago

The volume of a box is 10000 cm cube. the base is 25cm by 10 cm how tall is the box?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

8 0

Answer:

40cm

Step-by-step explanation:

1. 10000cm^3/25cm= 400cm^2

2. 400cm^2/10 cm= 40cm

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I don’t feel like typing it out but can you guys help me on this one

lara31 [8.8K]

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3 years ago

Read 2 more answers

-40-8b=-6(1+7b) what’s the answer

Andre45 [30]

$\text{Hey there!}$

$\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}$

$\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}$

$\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}$

$\mathsf{ADD\ by\ 42b\ on\ your\ sides}\\\mathsf{-8b-40+42b=-42b-6+42b}\\\mathsf{SOLVE\ above\ correct\ to\ get\ us\ to\ the\ next\ step!}\\\mathsf{\rightarrow 34b-40=-6}$

$\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}$

$\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}$

$\boxed{\boxed{\boxed{\boxed{\mathsf{Thus\ your\ answer\ is:\boxed{\boxed{\mathsf{b=1}}}}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

8 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$