After 24 hours, 35.4% of the initial dosage remains on the body.
<h3>What percentage of the last dosage remains?</h3>
The exponential decay is written as:

Where A is the initial value, in this case 2.8mg.
k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

The percentage of the initial dosage that remains is:

If you want to learn more about exponential decays:
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Hi there!
Let's solve this equation step by step!

First add 7 to both sides.

Next we need to take a look at the meaning of the stripes between our variable. Those stripes mean we are dealing with an absolute value function. The absolute value stripes make everything between the stripes positive; also when we plug in a number. In this particular question we can plug in both -13 and 13 at the position of n, because when -13 is made positive, it fulfils the equation.
Hence,

or

~ Hope this helps you!
I think that it might be 62,100 because the 6 is in the ten thousands place, and if you divide it by 10, 60,000/10, then it would be 6000. 60,000 is 10 times more than 6,000. Correct me if I'm wrong.
Answer:
k = 5
Step-by-step explanation:
The given line is y = 4x - 14.
The given point is (k, k + 1).
For this point, x = k and y = k + 1.
You substitute these equations into the line's equation to find the value of k.
(x = k)
(y = k + 1)
y = 4x - 14
(k + 1) = 4(k) - 14
Solve for k.
k + 1 = 4k - 14
Subtract k from both sides.
1 = 3k - 14
Add 14 to both sides.
15 = 3k
Divide both sides by 3.
15/3 = k
Simplify.
5 = k
And that's the answer!
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Answer:
they both have the scale factor of 16
Step-by-step explanation: