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Snowcat [4.5K]
2 years ago
12

How do you multiply 6 by 67 by 123 by 6789

Mathematics
2 answers:
Korolek [52]2 years ago
8 0

Answer:

1,00,900,987 would be the answer

Anastaziya [24]2 years ago
3 0

Answer:5,000

Step-by-step explanation:

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10+10 is the same as 11+11<br> do you understand?
vekshin1

Answer:

wow really omg!!!!!!!!

5 0
3 years ago
The student council at Livingston High School is making T-shirts to sell for a fundraiser, at a price of $16 apiece. The costs,
Allushta [10]

Answer:

5 shirts must be sold.

Step-by-step explanation:

First, set up the equation. Each shirt (x) is sold for $16:

For every amount (y) for x: (y)(x) = (16)(y)

The cost is $4, with the setup fee as $60.

(16)(y) = (4)(y) + 60

16y = 4y + 60

Isolate the variable (y). Note the equal sign, what you do to one side, you do to the other. First, subtract 4y from both sides.

16y (-4y) = 4y (-4y) + 60

16y - 4y = 60

12y = 60

Next, isolate the variable (y). Divide 12 from both sides.

(12y)/12 = (60)/12

y = 60/12

y = 5

5 shirts must be sold.

To check, plug in 5 for y in the equation:

16y = 4y + 60

16(5) = 4(5) + 60

Simplify.

16(5) = 4(5) + 60

80 = 4(5) + 60

80 = 20 + 60

80 = 80 (True).

~


7 0
3 years ago
8. Where will the hour hand of a clock stop if it starts:
Virty [35]

Answer:

a. 11

b. 9

Step-by-step explanation:

thats the answer

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B
inysia [295]

\large \bigstar \frak{ } \large\underline{\sf{Solution-}}

Consider, LHS

\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered}  \\  \\  \text{So, using this identity, we get} \\  \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

We know,

\begin{gathered}\boxed{\sf{  \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered}  \\

So, using this identity, we get

\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}

can be rewritten as

\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\  \\  \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}

<h2>Hence,</h2>

\begin{gathered} \\ \rm\implies \:\boxed{\sf{  \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}

\rule{190pt}{2pt}

5 0
2 years ago
Can someone please help with this asap its worth a lot of points. (: !!!
ladessa [460]

Answer:

8...the value of d variable =45 degree

corresponding angles are equal(reason)

9.

8 0
3 years ago
Read 2 more answers
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