-9x7 mutiplies to be -63, and add up to be -2.
Answer:
See below.
Step-by-step explanation:
Fifth root of 243 = 3,
Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),
then r^5( cos Ф + i sin Ф )^5 = 243(cos 240 + i sin 240).
Equating equal parts and using de Moivre's theorem:
r^5 =243 and cos 5Ф + i sin 5Ф = cos 240 + i sin 240
r = 3 and 5Ф = 240 +360p so Ф = 48 + 72p
So Ф = 48, 120, 192, 264, 336 for 48 ≤ Ф < 360
So there are 5 distinct solutions given by:
3(cos 48 + i sin 48),
3(cos 120 + i sin 120),
3(cos 192 + i sin 192),
3(cos 264 + i sin 264),
3(cos 336 + i sin 336).. (Answer).
Answer:
What are the two equations?
Step-by-step explanation:
Once u answer that I'll edit this and answer ur question :)
Answer:
9u
Step-by-step explanation:
18u³ / 9u = 2u²
45u²/9u = 5u
27u / 9u = 3
Answer:
The multiplicity of a root affects the shape of graph of a polynomial. If a root of a polynomial has odd multiplicity, the graph will cross the x-axis at the root. If a root of a polynomial has even multiplicity, the graph will touch the x-axis at the root but will not cross the x-axis
Step-by-step explanation:
Tbh I don't know the answer I just hope this helps
