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matrenka [14]
3 years ago
12

A large university accepts ​50% of the students who apply. Of the students the university​ accepts, ​50% actually enroll. If 10,

000 students​ apply, how many actually​ enroll?
Mathematics
1 answer:
german3 years ago
3 0

Answer:

5,000

Step-by-step explanation:

well if im right it should just be half, but unless im not reading this right then thats probably not it sorry if im wrong

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There are 40 students in a class, 12 girls and 28 boys. What is the probability of the complement (NOT picking a girl)?
Sveta_85 [38]

Answer:

28/40

Step-by-step explanation:

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5 0
3 years ago
Which solid has the top, the side, and the front views given?
cricket20 [7]

Answer:

H

Step-by-step explanation:

Only H looks like a square from the top.

Answer: H

5 0
3 years ago
It took 48 minutes to drive downtown. An app estimated it would be less than that. If the error was 20%, what was the app’s esti
IgorLugansk [536]

Answer:

The estimated taken to drive downtown using App is 38.4 minutes

Step-by-step explanation:

Given as :

The initial time taken to drive downtown = i = 48 minutes

The percentage error of time = r = 20%

Let The estimated time using app = t min

Let the time = 1 min

<u>Now, according to question</u>

The estimated time using app = The initial time taken to drive downtown × (1-\dfrac{\textrm rate}{100})^{\textrm time}

Or, t minutes = i minutes × (1-\dfrac{\textrm r}{100})^{\textrm 1}

Or, t = 48 minutes × (1-\dfrac{\textrm 20}{100})^{\textrm 1}

Or,  t = 48 minutes × \dfrac{100-20}{100}

Or,  t = 48 minutes × \dfrac{80}{100}

∴ t = \dfrac{48\times 80}{100} minutes

I.e t = 38.4 minutes

Or, The estimated time using app = t = 38.4 min

Hence, The estimated taken to drive downtown using App is 38.4 minutes Answer

5 0
3 years ago
a person invested $6700 for one year, part at 8%, part at 10%, and the remainder at 12%. the total annual income from these inve
lukranit [14]

Answer:

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

Step-by-step explanation:

step 1

Let

x-----> the amount invested at 8% rate

y-----> the amount invested at 10% rate

z-----> the amount invested at 12% rate

z=(x+y)+300 ----> equation A

x+y+z=6,700 ----> equation B

substitute equation A in equation B

x+y+(x+y+300)=6,700

2x+2y=6,400

x+y=3,200 -----> equation C

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=1\ year\\ P=\$6,700\\ I=\$716

substitute in the formula above

716=x(0.08)+y(0.10)+z(0.12)

substitute equation A

716=x(0.08)+y(0.10)+(x+y+300)(0.12)

716=0.08x+0.10y+0.12x+0.12y+36

716=0.20x+0.22y+36

0.20x+0.22y=680  -----> equation D

step 2

Solve the system of equations

x+y=3,200 -----> equation C

0.20x+0.22y=680  -----> equation D

Solve the system by graphing

The solution is the point (1,200,2,000)

see the attached figure

Find the value of z

z=(x+y)+300

z=(1,200+2,000)+300=3.500

therefore

The amount invested at 8% rate is $1,200

The amount invested at 10% rate is $2,000

The amount invested at 12% rate is $3,500

8 0
4 years ago
Without actual calculating the cubes, evaluate using identities:<br> <img src="https://tex.z-dn.net/?f=-11%5E3%2B8%5E3%2B3%5E3"
djyliett [7]

Answer:

-792

Step-by-step explanation:

5 0
2 years ago
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