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melisa1 [442]
3 years ago
8

Paul traded 13 baseball card to Dan for 4 new packs of 6 cards each. Paul lost 3 cards. He now has 75 cards. How many cards did

Paul have to begin with?
Mathematics
1 answer:
melomori [17]3 years ago
3 0

Answer:

The number of cards Paul had at the beginning was 64 cards

Step-by-step explanation:

Here we have a word problem as follows

Paul traded 13 baseball card to Dan for 4 new packs of 6 card each

Number of cards received from Dan = 6 × 4 = 24

Number of cards traded to Dan = 13

Net number of cards traded = 24 - 13 = 11

Total number of cards Paul now has = 75 cards

Therefore since Paul gained 11 cards to make his total number of cards = 75, then;

The initial amount of cards Paul had = 75 - 11 = 64 cards.

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Answer:

9 and a half inches

Step-by-step explanation:

Just count via the ruler!

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3 years ago
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If 1 16 oz can cost. $1 how much is 8 40oz cans
Studentka2010 [4]

Answer:

8 I think

Step-by-step explanation:

I did 40÷16=2.5 then 2.5×8=20

3 0
3 years ago
write the equation of the line (in slope-intercept form) that passes through the points (2,3 and (5,7)
AfilCa [17]

Answer:

The answer to your question is    y = 4/3x + 1/3

Step-by-step explanation:

Data

Point A = (2, 3)

Point B = (5, 7)

Process

1.- Calculate the slope

x1 = 2    y1 = 3

x2 = 5    y2 = 7

m = (y2 - y1)/(x2 - x1)

- Substitution

  m = (7 - 3)/(5 - 2)

- Slope

  m = 4/3

2.- Find the equation of the line

     y - y1 = m(x - x1)

     y - 3 = 4/3(x - 2)

     y - 3 = 4/3x - 8/3

     y = 4/3x - 8/3 + 3

     y = 4/3x - 8/3 + 9/3

     y = 4/3x + 1/3

8 0
3 years ago
I need some help on this ​
Musya8 [376]

Answer: A

Step-by-step explanation: A function means that your x can only have one y but your y can have multiple x's.

8 0
3 years ago
The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, gbb,
NNADVOKAT [17]

Answer:

bbbb,

bbbg, bbgb, bgbb, gbbb,

bbgg, bgbg, bggb, gbgb, gbbg, ggbb,

bggg, gbgg, ggbg, gggb,

gggg

Step-by-step explanation:

3 children: bbb, bbg, bgb, gbb, bgg, gbg, ggb, ggg

4 children: bbbb, bbbg, bbgb, bgbb, gbbb, bbgg, bgbg, bggb, gbgb, ggbb, bggg, gbgg, ggbg, gggb, gggg

You need to take a methodological approach;

The 2 easiest are the possibility of all boys and all girls;

Then consider 3 boys and 1 girl:

bbbg, bbgb, bgbb, gbbb

Then 2 boys and 2 girls:

bbgg, bgbg, bggb, gbgb, gbbg, ggbb

Lastly, 1 boy and 3 girls:

bggg, gbgg, ggbg, gggb

In total, there are 16 possibilities

P.S. interesting to note is that the number of possibilities here follows the pattern of Pascal's triangle:

       1

     1   1

   1  2  1

 1  3  3  1

1  4  6  4  1

The last row is relevant here;

There is 1 possibility where there are 4 boys;

There are 4 possibilities (in terms of the order of birth) where there are 3 boys and 1 girl;

There are 6 possibilities where there are 2 boys and 2 girls

There are 4 possibilities where there is 1 boy and 3 girls;

There is 1 possibility where there are 4 girls;

The pattern ∴ is 1 4 6 4 1, as the 5th row of Pascal's triangle reads;

If your talking about 3 children, it would match the 4th row of Pascal's triangle;

So, 1 possibility of 3 boys;

3 possibilities of 2 boys and 1 girl;

3 possibilities of 1 boy and 2 girls;

And 1 possibility of 3 girls;

If your talking about 10 children, it would match the 11th row of Pascal's triangle.

(Maths can be so cool XD)

7 0
3 years ago
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