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3 years ago

6

In Miss Marshalls classroom 6/7 of the students play sports of the students who play sports for fifth also play instruments if t

here are 35 students in her class how many play sports and instruments

1 answer:

Ostrovityanka [42]3 years ago

3 0

6/7 time 4/5 = 24/35
24 students do both.

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Following one side of a rural road, the house numbers increase by eighteen. The house number of the first house on the road is 8

ad-work [718]

Answer:

<u>Recursive:</u>

$a_n=a_{(n-1)}+18\\ \\ a_1=82$

<u>Explicit:</u>

$a_n=64+18n$

Explanation:

<u>1. Sequence:</u>

$a_1=82\\ \\ a_2=82+18=100\\ \\ a_3=100+18=118\\ \\ a_4=118+18=136\\ \\ ...$

<u>2. Recursive formula</u>

The recursive formula permits to calculate the value of the nth term in the sequence using the (n-1)th term in the sequence.

$a_n=a_{(n-1)}+18\\ \\ a_1=82$

<u>3. Explicit formula</u>

The explicit formula permits to calculate any value of a term in the sequence:

$a_n=a_1+(n-1)d\\ \\ a_n=82+(n-1)18\\ \\ a_n=82+18n-18\\ \\ a_n=64+18n$

7 0

3 years ago

Trisha and Byron are washing and vacuuming cars to raise money for a class trip. Trisha raised $38 washington 5 cars and vacuumi

ANEK [815]

Answer:

They charged <u>$6</u> for washing and <u>$2</u> for vacuuming the car.

Step-by-step explanation:

Let the charge of washing a car be 'x'.

And also let the charge of vacuuming a car be 'y'.

Now according to question, Trisha raised $38 washing 5 cars and vacuuming 4 cars.

So framing the above sentence in equation form, we get;

$5x+4y=38\ \ \ \ \ equation\ 1$

Again according to question, Byron raises $28 by washing 4 cars and vacuuming 2 cars.

So framing the above sentence in equation form, we get;

$4x+2y=28\ \ \ \ \ equation\2$

Now multiplying equation 2 by '2', we get;

$2(4x+2y)=28\times2\\\\8x+4y=56\ \ \ \ equation\ 3$

Now we subtract equation 1 from equation 3 and get;

$(8x+4y)-(5x+4y)=56-38\\\\8x+4y-5x-4y=18\\\\3x=18\\\\x=\frac{18}{3}=6$

Now substituting the value of 'x' in equation 1, we get;

$5x+4y=38\\\\5\times6+4y=38\\\\30+4y=38\\\\4y=38-30=8\\\\y=\frac{8}{4}=2$

Hence They charged <u>$6</u> for washing and <u>$2</u> for vacuuming the car.

8 0

3 years ago

The formula I = PRT where I = Interest, P = principal, R = rate, and T = time is used to calculate the amount of simple interest

andre [41]

Answer:

Step-by-step explanation:

as

I=PRT

SO

T=I/PR

6 0

3 years ago

Lucy is on her way home in her car. She has driven 22 miles so far, which is one-half of the way home. What is the total length

Ket [755]

Answer:

44

Step-by-step explanation:

if 22 miles = 1/2

then, 22 times 2 = 44 miles

ANSWER= 44 miles

5 0

3 years ago

Line segment 19 units long running from (x,0) ti (0, y) show the area of the triangle enclosed by the segment is largest when x=

Debora [2.8K]

The area of the triangle is

A = (xy)/2

Also,

sqrt(x^2 + y^2) = 19

We solve this for y.

x^2 + y^2 = 361

y^2 = 361 - x^2

y = sqrt(361 - x^2)

Now we substitute this expression for y in the area equation.

A = (1/2)(x)(sqrt(361 - x^2))

A = (1/2)(x)(361 - x^2)^(1/2)

We take the derivative of A with respect to x.

dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]

dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]

Now we set the derivative equal to zero.

(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0

-2x^2 + 361 = 0

-2x^2 = -361

2x^2 = 361

x^2 = 361/2

x = 19/sqrt(2)

x^2 + y^2 = 361

(19/sqrt(2))^2 + y^2 = 361

361/2 + y^2 = 361

y^2 = 361/2

y = 19/sqrt(2)

We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.

3 0

3 years ago