Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
You could put the ‘+6’ at the start of the equation so it would read as +6(x2+8x) and then expand the bracket as you normally would so you would get x2x6 which would get you 12x and then 6x8x which would get you 48x and then you could group both numbers together as they’re like terms and your final answer would be 60x
Answer:
4
Step-by-step explanation:
25/100 x 80/1 = 20/1
80 - 20 = 60
30/100 x 80/1 = 24/1
80 - 24 = 56
60-56=4
Answer:
substitute 3 as in x:
4(3)-9
= 12-9
= 3
Hope this helped - have a nice day & be safe
