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2 years ago

Surface Area Of A Prism

Mathematics

1 answer:

Yakvenalex [24]2 years ago

6 0

surface area of a rectangular prism

A=2(wh+lw+lh)

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What is the relationship between the area of the rectangle ABCD and triangle ABC?

Sonja [21]

Answer:

The second one.

Step-by-step explanation:

The area of the triangle has an area that is half the area of the rectangle.

A straight line divides the rectangle directly in half, creating two triangles, each triangle being half the area of the rectangle

6 0

2 years ago

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if 36 cookies cost $4.00 what is the unit rate in cookies per dollar. Using the same information what is the unit rate for 1 coo

pogonyaev

Answer:

9 cookies per dollar

Step-by-step explanation:

This is a fraction equal to

36 cookies ÷ 4 dollars

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 4

36 cookies ÷ 4

--------------------------

4 dollars ÷ 4

9 cookies

---------------

1 dollar

9 cookies

-----------------

dollar

= 9 cookies per dollar

3 0

2 years ago

HELPPPPPPPPPPPPPPPPPPP!!!

Angelina_Jolie [31]

Answer:

15.13cm

Step-by-step explanation:

From that above question:

We are told that:

Lateral surface area of a right circular cone : πr√r² + h²

We are give the following parameters:

Lateral surface area = 236.64cm²

Radius = 4.75cm

We are to find the height

Making h the subject of the formula

h = √[(A/r)² - πr²]/π

h = √[(236.64/4.75)²- π ×4.75²]/π

h = 15.12975 cm

Approximately to the nearest hundredth = 15.13cm

7 0

2 years ago

3k-2=10 whats the answer

kap26 [50]

Answer:

k = 4

Step-by-step explanation:

3k - 2 = 10

3k - 2 + 2 = 10 + 2 (adding 2 to both sides)

3k = 12

3k/3 = 12/3 (dividing both sides by 3)

k = 4

Happy to help :)

4 0

2 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers