First, write out the statement as an inequality so that it looks like this: x<span>≤11/5
Then you graph it on a number line, and since you know anything greater/less than or equal to is a closed circle since it includes the value 11/5, you would plot a closed circle on 11/5 on a number line and draw and arrow pointing towards the left to show that only values 11/5 or under can satisfy x.
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Y = -1/5x + 2
A line perpendicular to another line has an opposite reciprocal slope. What opposite means is that you flip the sign (from - to + or from + to -) and reciprocal means that you flip the numerator and denominator (so if line A is perpendicular to line B and line As slope is -3, line Bs slope would be 1/3).
First find the slope of 5x - y = -3
Add y to both sides
5x = y - 3
Add 3 to both sides
y = 5x + 3
So the slope of the line is 5. That means the slope of of the perpendicular line is -1/5.
Plug the slope of the perpendicular line and the point (5, 1) into point slope form to solve the equation
y - y1 = m(x - x1)
y - 1 = -1/5(x - 5)
y - 1 = -1/5x + 1
y = -1/5x + 2
Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm
Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams
Answer:
Step-by-step explanation:
Technically a biology question but if you create the chart all 4 types will be Tt because the Male has the genotype of TT so they will each have a large T in each box (like making a multiplication table). and the female has tt so the only possibility is a large T with a small t in all four squares because there are both homogenous genotypes. (the bottom-most answer is the correct answer)
