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posledela
4 years ago
13

Can anybody help me with this please??

Mathematics
1 answer:
Verizon [17]4 years ago
3 0

Answer:

x = 5

Step-by-step explanation:

\frac{10}{x} = \frac{14 + 10}{2x - 3 + x}

\frac{10}{x}  = \frac{24}{3x - 3}

24 x = 10 . (3x - 3)

24x = 30 x - 30 \\6x = 30 \\x = 5

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Jack's father is three times older than Jack. Five years ago, the sum of their ages was 34. How old is Jack's father now?.
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3 years ago
PLZZ HELPP is this positive negative or zero
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Need help asap please
jonny [76]

Answer:

B. x= 4

Step-by-step explanation:

We know that,

The result for the intersection of the secant and the tangent is given by by the figure below,

UV^{2}=UX\times UY

According to the question, we have,

8^{2}=x(12+x)

i.e. 64=12x+x^2

i.e. x^2+12x-64=0

Now, the solution of a quadratic equation ax^2+bx+c=0 is given by, x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So, we get,

x^2+12x-64=0 implies a= 1, b= 12 and c= -64.

Thus, the solution is given by,

x=\frac{-12\pm \sqrt{12^{2}-4\times 1\times (-64)}}{2\times 1}

i.e. x=\frac{-12\pm \sqrt{144+256}}{2}

i.e. x=\frac{-12\pm \sqrt{400}}{2}

i.e. x=\frac{-12\pm 20}{2}

i.e. x=\frac{-12-20}{2} and i.e. x=\frac{-12+20}{2}

i.e. x=\frac{-32}{2} and i.e. x=\frac{8}{2}

i.e x= -16 and x= 4.

Since, length cannot be negative.

So, we have, x= 4.

8 0
3 years ago
Is it possible to write an equation for such a
valentinak56 [21]
Yes it is possible to write an equation for such a parabola in the form
6 0
3 years ago
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