triangle abc has the vertices A (0,10) B (4,10) C( -2,4). Find the orthocenter of ABC. A -2,-12 B 2,-12 C 12,-2 D-12,2
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Answer:
∴ The the surface area of the wall is .
Step-by-step explanation:
Given that,
The length of rectangular wall is .
The width of rectangular wall is
The length of doorway is
The width of doorway is
and, we have to find the surface area of rectangular wall.
Now,
The length of rectangular wall is .
The width of rectangular wall is
∴ Total surface area of a rectangular wall
Total surface area of a rectangular wall is .
Again, The length of doorway is
The width of doorway is
∴Total surface area of doorway
Total surface area of doorway is .
∴The remaining surface area of a rectangular wall is
∴ The the surface area of the wall is .