triangle abc has the vertices A (0,10) B (4,10) C( -2,4). Find the orthocenter of ABC. A -2,-12 B 2,-12 C 12,-2 D-12,2
1 answer:
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Answer:
Prime.
Step-by-step explanation:
First let's multiply our outer coefficients in this case 1 and 8, so we have 1x8=8. Now the point of this is to get the factors of 8 and see if we can get that middle term -7. Factors of 8 are 1x8, 2x4 and that's it. From there I notice that -8+1 = -7 and so:
Notice that the (x-8) and (x+8) are not the same factors, therefore the factors are not any of those answer choices and so it's prime. You can calculate the factors by using the quadratic formula, however I think that is beyond the scope of this question.
