Answer:
Let's call the length of the field "l", and the width of the field "w".
If the area of the field is 72 square meters, then we have:
l x w = 72
And if the length is 6 meters longer than the width, we have:
l = w+6
So looking at the first equation (l x w = 72), we can substitute the l for a w+6.
And we obtain:
(w+6) x (w) = 72
Which simplifies to w^2 + 6w = 72.
This quadratic equation is pretty easy to solve, you just need to factor it.
w^2 + 6w - 72 = 0
(w-6)(w+12)
This leaves the roots of the quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.
So, the width of the rectangular field is 6, and the length of the field is 12.
Let me know if this helps!
Step-by-step explanation:
f(x) = x³ − 6x² + 9x + 3
Take the derivative and evaluate at x = 2.
f'(x) = 3x² − 12x + 9
f'(2) = -3
Check for local minimums or maximums by setting f'(x) equal to 0.
0 = 3x² − 12x + 9
0 = x² − 4x + 3
0 = (x − 1) (x − 3)
x = 1 or 3
Evaluate f(x) at the critical values, and at the end points.
f(0) = 3
f(1) = 7
f(3) = 3
f(5) = 23
f(x) has a minimum of 3 and a maximum of 23.
About 20 liters( I rounded based on the rules for multiplying significant figures)
180 degrees - 116 degrees =64 degrees (angle PDC)
180 degrees - 64 degrees = 116 degrees (angle APD)
<span>No solution.
Because once the </span><span>|–3x + 9| is done the resulting answer is positive.
3*Positve cannot be = -18.
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