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vitfil [10]
3 years ago
14

The value of a dirt bike decreases by 30% each year. If you purchased this dirt bike today for $500, to the nearest dollar how m

uch would the bike be worth 5 years later?
$84
$119
$164
$222
Mathematics
2 answers:
salantis [7]3 years ago
5 0
It starts at $500, then decreases by 30% so just multiply 500 by .7, then multiply the answer by .7, and so on until you get to $84.
Burka [1]3 years ago
4 0

Answer:

After 5 years cost of the dirt bike will be $84.

Option A is the answer.

Step-by-step explanation:

The value of a dirt bike decreases by 30% each year. If the present cost of the dirt bike is $500.

Then the function which defines the decrease in cost of the bike will be

f(t)=a(r)^{t}

where a = $500

After one year decrease in the cost of the bike will be = 500×0.30 = $150

The cost of the bike next year will be = 500-150 = $350

So the sequence for the cost every year will be 500, 350..........

Now the common ratio of the sequence will be = \frac{350}{500}=0.70

Now we can form the explicit formula for this geometric sequence as

a_{n}=a(r)^{n}

a_{n}=500(0.70)^{n} where n is the time in years.

For t = 5 years

a_{5}=500(0.70)^{5}

a_{5}=500(0.168)

a_{5}=84.035

Therefore, after 5 years cost of the dirt bike will be $84.

Option A is the answer.

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The amount of money Debby owes her sister is $9.

<h3>How much does Debby owe her sister? </h3>

When Debby borrows money, the amount of her debt increases and when she pays back her debt decreases. So, when she borrows, the amount she borrows is added and when she pays back, the amount is subtracted.

$10 - $5 + 4 = $9

To learn more about addition, please check: brainly.com/question/19628082

6 0
2 years ago
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SVEN [57.7K]

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3 years ago
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aliya0001 [1]

Answer:

10

Step-by-step explanation:

so since

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katrin2010 [14]

Answer:

\log 4^{\frac{1}{8}}=0.07525\\\\\log 100^{0.001}=0.002\\\\\log 8^{0.00625}==0.00564375

Step-by-step explanation:

Property of Log used here: \log m^n=n\log m,\ \log 2=0.3010299957,\ \log 10=1

1.

\log 4^{\frac{1}{8}}=\frac{1}{8}\log 4\ \ \ \ \ \ \ \ \ \ using\ \log m^n=m\log n\\\\\log 4^{\frac{1}{8}}=\frac{1}{8}\log 2^2\\\\\log 4^{\frac{1}{8}}=\frac{1}{8}\times 2\log 2\ \ \ \ \ \ \ \ \ \ using\ \log m^n=m\log n\\\\\log 4^{\frac{1}{8}}=\frac{1}{4}\times 0.3010\\\\\log 4^{\frac{1}{8}}=0.07525

2.

\log 100^{0.001}=0.001\log 100\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ using\ \log m^n=n\log m\\\\\log 100^{0.001}=0.001\log 10^2\\\\\log 100^{0.001}=0.001\times 2\log 10\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ using\ \log m^n=n\log m\\\\\log 100^{0.001}=0.001\times 2\ \ \ \ \ \ \ \ \ \ \ \ as\ \log 10=1\\\\\log 100^{0.001}=0.002

3.

\log 8^{0.00625}=0.00625\log 8\ \ \ \ \ \ \ \ \ \ using\ \log m^n=m\log n\\\\ \log 8^{0.00625}=}=0.00625\log 2^3\\\\\\log 8^{0.00625}==0.00625\times 3\log 2\ \ \ \ \ \ \ \ \ \ using\ \log m^n=m\log n\\\\\log 8^{0.00625}==0.00625\times 3\times 0.3010\\\\\log 8^{0.00625}==0.00564375

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Answer:

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|55|

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