Answer:
yes i do believe so
Step-by-step explanation:
Answer:
33×33+33-33÷0=infinity
33×33=1089
33-33=0
Taking L.H.S
=33×33+(33-33)÷0
=1089+0÷0
=1089÷0
=infinity
L.H.S=R.H.S
Step-by-step explanation:
The percent is 145. That should be your answer
For the given sequence we have the formula:
Sₙ = 1 + (n - 1)*2
The 50th square will have 99 shaded squares.
<h3 /><h3>
How many shaded squares are on the n-th square?</h3>
Here we have a sequence:
The first square has 1 shaded squares.
the second square has 3 shaded squares.
The third square has 5 shaded squares.
And so on.
Already you can see a pattern here, each next step we add 2 shaded squares, then we can write the formula:
Sₙ = 1 + (n - 1)*2
Where S is the number of shaded squares and n is the number of the figure.
Then the 50th square will have:
S₅₀ = 1+ (50 - 1)*2 1 + 49*2 = 99
Learn more about sequences:
brainly.com/question/6561461
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So we see our equation, clear:
y=8^x
Let's just plug in values of x from 1-4.
y= 8^1=8; So, it would be (1,8).
y= 8^2=64; So, it would be (2, 64).
y = 8^3= 512; So, it would be (3,512).
y= 8^4 = 4096; So, it would be (4, 4096).
