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Darya [45]
4 years ago
6

If the radius of a circle is 15 units and the center

Mathematics
1 answer:
Verdich [7]4 years ago
8 0

Answer:

C. (x+3)^2 + (y-2)^2 = 225

Step-by-step explanation:

The equation of the circle is (x-h)^2 +  (y-k)^2 = r^2

h=-3, k=2 and r=15

(x-(-3))^2 + (y-2)^2 =15^2

(x+3)^2 + (y-2)^2 = 225

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Anestetic [448]
1) 65+57= 122
180-122= 58

2) 40+90=130
180-130=50

3) 130+20=150
180-150=30

4) 85+50= 135
180-135=45

Sorry, IDK the rest. So so sorry.
8 0
4 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)
Romashka [77]

Answer:

The amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

Step-by-step explanation:

The given function is

f(t)=-\frac{1}{2}\sin (3t-2\pi)      .... (1)

The general form of sine function is

F(t)=A\sin (Bt-C)+D                 ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

A=-\frac{1}{2}

B=3

C=2\pi

D=0

So,

amplitude=|A|=\frac{1}{2}

period=3

\text{phase shift}=\frac{2\pi}{3}

Therefore amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

8 0
4 years ago
What happens if you label the starting number x
tester [92]
You can use any letter but when you label it x you find x
3 0
3 years ago
A communications company is planning to launch a new satellite into orbit to improve the operation of its network. The longest d
sergiy2304 [10]
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3 0
3 years ago
The quadratic equation is
NemiM [27]

Answer:

(2,-9)

Step-by-step explanation:

Set the quadratic equal to zero.

y =  {x}^{2}  - 4x  -  5

Factor

(x - 5)(x + 1)

Set each of these factors to zero

x - 5 = 0

and

x + 1 = 0

x = 5

and

x =  - 1

Plot the midpoint of the two values.

( \frac{5 + ( - 1)}{2} ) = 2

So the middle term is 2 and the other terms are 5 and -1.

Now the vertex is

2 {}^{2}  - 4(2) - 5 =  - 9

So the vertex is

(2,-9)

8 0
3 years ago
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