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Veseljchak [2.6K]
3 years ago
9

when graphing a system of equations with "the same"or "different" in order to make the sentence a true statement ______________.

Mathematics
1 answer:
marishachu [46]3 years ago
4 0
You must use x and y to solve a graphing problem
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khan academy is giving me only this explanation but won't go into detail and I cannot understand it for the life of me. how do I
Setler [38]

Answer:

12 - 4i

Step-by-step explanation:

-2i ( 2+6i)

Distribute

-2i * 2 + -2i *6i

-4i - 12 i^2

We know that i^2 = -1 so replace it

-4i - 12(-1)

-4i + 12

Then put in the order a+bi  where the real number comes first and the imaginary number comes last

12 - 4i

7 0
3 years ago
Jayden has been reading a 275275275-page book for English class. On average, he has read about 101010 pages in 151515 minutes (\
maxonik [38]
First let's define variables:
 r: reading
 s: skimming
 We write the system of equations that adapts to the problem:
 r + s = 275
 (15/10) r + (10/15) s = 355
 We solve the system of equations:
 r = 206
 s = 69
 Note: see attached image for system solution.
 Answer: 
 Jayden had to skim 69 pages through

8 0
3 years ago
Please answer this<br>Hope you get along<br>I report What to answer​
Llana [10]

What the hel you expect us to do all that for 5 kids points? Go ask you mom to do that for you. If you're asking US to do that, then it has to be 40 or 50 points.

3 0
3 years ago
A chemist wants to make 100 liters of a 44% acid solution. She has solutions that are 20% acid and 60% acid.
alexgriva [62]

the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

7 0
2 years ago
Which expression is equivalent?
MrMuchimi

Answer:

The Third one.

Step-by-step explanation:

So, Turn the mixed number, 2 1/4, to an improper fraction, 9/4. Then match the answer!

If you need anything else, just message me!

Have a nice day! :)

8 0
2 years ago
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