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3 years ago

when graphing a system of equations with "the same"or "different" in order to make the sentence a true statement ______________.

Mathematics

1 answer:

marishachu [46]3 years ago

4 0

You must use x and y to solve a graphing problem

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19. What are the extremes of the following proportion? 3⁄15 = 12⁄60

insens350 [35]

4 is your answer

3 x 4 = 12
15 x 4 = 60

so 4 is the amount
hope this helps

8 0

3 years ago

Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>

Alla [95]

$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

$\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}$

$\boxed{ \tt \red{C}arry \: \red{ O}n \: \red{L}earning} \: \underline{\tt{5/13/22}}$

4 0

2 years ago

How do we get to the vertex if this is the function: n(x)= |-1/3x + 1| =2 ??

vagabundo [1.1K]

Answer:

ANSWER IS BELOW

Step-by-step explanation:

Find the properties of the given parabola.

Tap for more steps...

Direction: Opens Up

Vertex:

(

)

(0,0)

Focus:

(

)

(0,34)

Axis of Symmetry:

x=0

Directrix:

−

y=-34

Select a few

values, and plug them into the equation to find the corresponding

values. The

values should be selected around the vertex.

Tap for more steps...

−

xy-243-1130011333

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:

(

)

(0,0)

Focus:

(

)

(0,34)

Axis of Symmetry:

x=0

Directrix:

−

y=-34

−

xy-243-1130011333

3 0

3 years ago

What is 2/3÷6 over five

malfutka [58]

5/9 (fraction simplified)

7 0

3 years ago

The vertex angle of isosceles triangle is 110. what are the measures of the base angles

alexgriva [62]

Two sides are equal in an isosceles triangle. This means that the angle both sides make with the third side must be the same. Since the angles in a triangle add up to 180°, you can subtract 110° from 180° and divide your answer by two. The resulting number will be the measure of each of the two unknown angles

3 0

2 years ago