Any point on the x-axis beyond the point (4, 0) is a possible cordinate of R.
Answer:
No solutions.
Step-by-step explanation:
-2x - y = 1
-4x - 2y = -1 Multiply the first equation By -2:
4x + 2y = -2 Adding:
0 = -3
which is absurd so there are no solutions.
Answer:
see explanation
Step-by-step explanation:
Since KL = KM then the triangle is isosceles and the 2 base angles are congruent, that is
∠KLM = ∠KML, thus
y - 9 = x + 4 (add 9 from both sides )
y = x + 13 → (1)
The sum of the 3 angles in the triangle = 180°, thus
x + 4 + y - 9 + x + y + 3 = 180
2x + 2y - 2 = 180 ( add 2 to both sides )
2x + 2y = 182 → (2)
Substitute y = x + 13 into (2)
2x + 2(x + 13) = 182 ← distribute and simplify left side
2x + 2x + 26 = 182
4x + 26 = 182 ( subtract 26 from both sides )
4x = 156 ( divide both sides by 4 )
x = 39
Substitute x = 39 into (1)
y = 39 + 13 = 52
Hence
∠K = x + y + 3 = 39 + 52 + 3 = 94°
Answer:
Go 4 to the right and 2 down.
