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3 years ago

(-4,2) (2-3) midpoint

Mathematics

1 answer:

Sedbober [7]3 years ago

3 0

Answer:

(-1, -1/2)

Step-by-step explanation:

use the midpoint formula(x1+x2/2, y1+y2/2)

-4+2/2, 2+-3/2

-4+2=-2/2=-1

2+-3=-1/2

(-1, -1/2)

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Help me i don’t know how to do this

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Hi!

y = 16

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<h3 /><h3>In 30-60-90 triangles, the hypotenuse is double the length of the shortest leg, and the longer leg is $\sqrt{3}$ times the shorter leg.</h3>

We are given the longest leg. To find the shortest leg, we must divide the longest leg value by $\sqrt{3}$

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The radicals cancel out and we are left with 16.

The length of y (the shortest leg) is 16.

Now, we also know that the hypotenuse is double the shortest leg. The shortest leg is 16, so if we double that, it's 32.

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3 years ago

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levacccp [35]

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3 years ago

How to show these 2 problems are inverses

nataly862011 [7]

$\bf \begin{cases}
f(x)=\sqrt[3]{7x-2}\\\\
g(x)=\cfrac{x^3+2}{7}
\end{cases}\\\\
-----------------------------\\\\
now
\\\\
f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2}
\\\\\\
\sqrt[3]{x^3}\implies x\\\\
-----------------------------\\\\
or
\\\\
g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7}
\\\\\\
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thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other

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3 years ago