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valentina_108 [34]
3 years ago
9

Factor completely 2x⁴y³-12x³y²-8x²y

Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0
This is what I got, hope this helped:)

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Can I have these questions answered,
weeeeeb [17]
1. 37.0952380952 or if rounded 38
2. 49.05 or if rounded 49.1 or 49
3. 2.84375 or if rounded 2.8 or 3
3 0
3 years ago
The volumes of two spheres are in a ratio of 1:8 what is the eatio rafi
Agata [3.3K]
Remark
I take it that you want to know the ratio of the radii. If this is not correct, leave a comment below my answer.

You could do this by giving the spheres a definite volume, like 1 and 8 and then solve for r for one of them and then use the other sphere to find it's radius. It is not exactly the best way, and if you are going to to a physics class you want to be doing this using cancellation. 

Step One 
Set up the Ratio for the volumes.

\frac{V_1}{V_2} =  \frac{1}{8}

Step Two
Setup the equation for V1/V2 using the definition for a sphere. V = 4/3 pi r^3

\dfrac{1}{8} =  \frac{ \frac{4}{3} \pi( r_1)^3 }{ \frac{4}{3} \pi( r_2)^3 }

Step Three
Cancel the 4/3 and pi on the top and bottom of the fractions on the right.

You are left with 1/8 = (r1)^3/ (r2)^3

Step Four
Take the cube root of both sides.
cube root 1/8 = 1/2

Cube root of (r1)^3 = r1
Cube root of (r2)^3 = r2

Step  Five
Answer
\frac{r_1}{r_2} =  \frac{1}{2}   Answer <<<<<<<
8 0
3 years ago
What is the solution to the equation 9^(−3x) ≈ 7?
Paraphin [41]

9^{-3x}=7\ \ \ \ |ln\\\\\ln9^{-3x}=\ln7\ \ \ \ |use\ \log a^n=n\log a\\\\-3x\ln9=\ln7\ \ \ \ |:(-3\ln9)\\\\x=\dfrac{\ln7}{-3\ln9}\to x\approx-\dfrac{1.9459}{3\cdot2.1972}\to x\approx-0.295\\\\Answer:\ c)\ x=-0.295

6 0
3 years ago
Read 2 more answers
Equation of a line that is perpendicular to the graph of y = 2/5x-1
inessss [21]

Answer:

-5/2

Step-by-step explanation:

8 0
2 years ago
What is the 8th term in the sequence? 14, 18, 116, 132, ...
polet [3.4K]
a_1=14;\ a_2=18\\\\d=a_2-a_1\to d=18-14=4\\\\a_n=a_1+(n-1)d\\\\a_n=14+(n-1)\cdot4=14+4n-4=10+4n\\\\a_8=10+4\cdot4=10+16=36\\\\Answer:\boxed{a_8=36}
4 0
3 years ago
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