Answer:
B
Step-by-step explanation:
You have to add 7 to both sides to isolate the variable
The answer to this is .15%
Answer: Our required equation would be 
Step-by-step explanation:
Since we have given that
Amount that Anderson earns per hour = $6
According to question, Anderson earns $1 more than half of Carey's hourly rate.
Let the hourly rate of Carey be 'c'.
So, it becomes,
And the value of c would be
Hence, our required equation would be
Answer:
0.332
Step-by-step explanation:
given series
1/4, 1/16,1/64.1/256
this is geometric series
where common ratio r is given by
nth term/ (n-1)th term
let the second term is nth term and first term is (n-1)th term
r = 1/16 / (1/4) = 1/4
___________________________________________
sum of series is given by
a (1-r^n)/1-r
where a is first term
n is the number of terms
r is the common ration
___________________________________________
in the given series
1/4, 1/16,1/64.1/256
a = 1/4
r = 1/4
n = 4
thus ,
sum = 1/4(1-(1/4)^4)/ (1-1/4)
sum = 1/4(1-(1/256)/(4-1)/4
sum = 1/4((256-1)/256 / 3/4
1/4 in numerator and denominator gets cancelled
sum =( 255/256*3) = 255/768 = 0.332
Thus, sum of series is 0.332.
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
