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Andrew [12]
3 years ago
10

Write an application that inputs a telephone number as a string in the form (555) 555-5555. The application should use String me

thod split to extract the area code as a token, the first three digits of the phone number as a token and the last four digits of the phone number as a token. The seven digits of the phone number should be concatenated into one string. Both the area code and the phone number should be printed. Remember that you will have to change deliminator characters during the tokenization process.
Computers and Technology
1 answer:
Scilla [17]3 years ago
8 0

Answer:

See explaination

Explanation:

// File: TelephoneNumber.java

import java.util.Scanner;

public class TelephoneNumber

{

public static void main(String[] args)

{

Scanner input = new Scanner(System.in);

String inputNumber;

String tokens1[];

String tokens2[];

String areaCode;

String firstThree;

String lastFour;

String allSeven;

String fullNumber;

/* input a telephone number as a string in the form (555) 555-5555BsAt4ube4GblQIAAAAASUVORK5CYII= */

System.out.print("Enter a telephone number as '(XXX) XXX-XXXX': ");

inputNumber = input.nextLine();

System.out.println();

/* use String method split */

tokens1 = inputNumber.split(" ");

/* extract the area code as a token */

areaCode = tokens1[0].substring(1, 4);

/* use String method split */

tokens2 = tokens1[1].split("-");

/* extract the first three digits of the phone number as a token */

firstThree = tokens2[0];

/* extract the last four digits of the phone number as a token */

lastFour = tokens2[1];

/* concatenate the seven digits of the phone number into one string */

allSeven = firstThree + lastFour;

/* concatenate both the area code and the seven digits of the phone number into one full string separated by one space */

fullNumber = areaCode + " " + allSeven;

/* print both the area code and the phone number */

System.out.println("Area code: " + areaCode);

System.out.println("Phone number: " + allSeven);

System.out.println("Full Phone number: " + fullNumber);

}

}

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Answer:

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AG 1.

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AG 4.

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Simply stated, ordered events are organized in order of time and this process is known as chronology.

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5 0
3 years ago
I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
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Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

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// method to quick sort the elements in the two arrays

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// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

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{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

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