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3 years ago

13

Mr.jone wants to buy 6 tickets to a play.Each ticket costs $10 Mr.Jone has $45 in his pocket. How much more money does he need t

o buy 6 tickets?

2 answers:

Snowcat [4.5K]3 years ago

8 0

He needs $15 more to buy the tickets.

ohaa [14]3 years ago

5 0

6 tickets at $10 a piece is $60 total.
$60 - $45 = $15

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-10<br> I will give brainliest answer instantly if correct

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Answer:

wait what? Lol thanks for the points luv <3

Step-by-step explanation:

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3 years ago

You roll two six-sided fair nukber cubes.Whatbis the probability that you will roll snake eyes(both ones)?

Katyanochek1 [597]

Answer:

1/36

Step-by-step explanation:

Each dice has a 1 in 6 chance to land on a 1, but for both dice to land on 1's it would be $(\frac{1}{6} )(\frac{1}{6})$ = $\frac{1}{36}$

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3 years ago

High school math help please (20 points for 3 problems, but if you could even answer 2 that would help. Please explain how you g

ipn [44]

Answer:

To question 1: van=9, bus=60

To question 2: Sorry, I don't know the answer.

To question 3: skate rental fee=$2.50, admission fee=$3.25

Step-by-step explanation:

Question 1:

Step 1 - set up equations

14v+16b=1,086

10b+13n=870

Step 2 - Solve for variable (in this case v)

10v+13b=870

Subtract 13b from both sides

10v=-13b+870

Divide both sides by 10

V=-1.3b+87

Step 3 - substitute the v in equation and solve

14 (-1.3b+87)+16b=1,086

-18.2b+1,218+16b=1,086

Combine like-terms

-2.2b+1,218=1,087

Subtract 1,218 from both sides

-2.2b=-132

Divide both sides by -2.2

B=60

Step 4 - substitute for b and solve

10v+13(60)=870

10v+780=870

Subtract 780 from both sides

10v=90

Divide both sides by 10

V=9

Question 3:

Step 1 - set up equations

5s+6f=32

5s+7f=35.25

Step 2 - solve for variable (in this case s)

5s+6f=32

Subtract 6f from both sides

5s=-6f+32

Divide both sides by 5

S=-1.2f+6.4

Step 3 - substitute for s and solve

5(-1.2f+6.4)+7f=35.25

-6f+32+7f=35.25

Combine like-terms

F+32=35.25

Subtract 32 from both sides

F=3.25

Step 4 - substitute for f

5s+6(3.25)=32

5s+19.5=32

Subtract 19.5 from both sides

5s=12.5

Divide both sides by 5

S=2.5

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3 years ago

A box contains blue and red pens. 2/5 of the pens are red. What is the ratio of blue to red pens?

Slav-nsk [51]

Answer:

3:2

Step-by-step explanation:

$\frac{5}{5} - \frac{2}{5} = \frac{3}{5}$

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3 years ago

A company considers buying a machine to manufacture a certain item. When tested, 28 out of 600 items produccd by the machine wer

weqwewe [10]

Answer:

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject $H_0$ , as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

Step-by-step explanation:

The null and alternate hypothesis are:

H0:p≥0.03

Ha:p<0.03

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis:

This means that $\mu = 0.03, \sigma = \sqrt{0.03*0.97}$

28 out of 600 items produced by the machine were found defective.

This means that $n = 600, X = \frac{28}{600} = 0.0467$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.0467 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{600}}}$

$z = 2.4$

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.0467, which is the p-value of z = 2.4.

Looking at the z-table, z = 2.4 has a p-value of 0.9918.

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject $H_0$ , as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

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3 years ago